PREG match all characters?

[sphinx]

Hello.

 

Is there a way to make preg_match match all content such as:

 

<a href="/cashback.aspx?linkauth=MATCHEVERYTHINGHERE&mpurl=test&usr=test">

 

The linkauth has a random string on numbers and characters on a webpage that I want to grab based on that format.

 

Thanks.

[jazzman1]

This will match only letters inside a character class closing with brackets ([ ]), between "=" and  "&" symbols.

$url = '<a href="/cashback.aspx?linkauth=MATCHEVERYTHINGHERE&mpurl=test&usr=test">';

if(preg_match('~=([A-Za-z]+)&~', $url, $match)) {
    echo '<pre>'.print_r($match[1], true).'</pre>';
} else {
   echo 'No match'; 
}

Or.....everything between these two symbols:

$url = '<a href="/cashback.aspx?linkauth=MATCHEVERYTHINGHERE&mpurl=test&usr=test">';

if(preg_match_all('~=([A-Za-z]+)&?~', $url, $match)) {
    echo '<pre>'.print_r($match[1], true).'</pre>';
} else {
   echo 'No match'; 
}

[AbraCadaver]

I would think with this simple example:

$pattern = '#linkauth=([^&]+)';

[.josh]

 

$pattern = '#(?:\?|&)linkauth=([^&\'"]+)#';

 

make sure it's linkauth and not someothervarendswithlinkauth. Also cover for if it's the last url param.

[AbraCadaver]

[sphinx]

This works perfectly.

 

<?php $url = '<a href="/cashback.aspx?linkauth=MATCHEVERYrtyTHINGHERE&mpurl=test&usr=test">'; if(preg_match('~=([A-Za-z]+)&~', $url, $match)) {    echo '<pre>'.print_r($match[1], true).'</pre>';} else {   echo 'No match'; } ?>

 

However, I need it to grab the content from  a specific URL in the exact same format.