Who can solve this problem?

[h1234]

i have put 3 users on my database. If i login with all 3 it works there is no problem(providing  correct username and password matches).
The problem is that it recognizes all 3 users as the first user. even if i check password it will display all three users password the same(all tho when i log in i have to have correct password and username for each user)

 

as the first user which is user id 1. When i echo username or name or surname it displays the first users name or surname whatever i echo , no matter who i log in with
 
I am not sure whats going on here at all.  here is my code for the login functions i think the problems lies here

 i know this is not the best code but there must be a way to fix this 

 

users.php
 
 

<?php

function register_user($register_data){
	Global $dbc;

array_walk($register_data,'array_sanatize');


$register_data['password']= md5($register_data['password']);

$fields='`'.implode('`, `',array_keys( $register_data)).'`';



$data='\''.implode('\', \'', $register_data).'\'';


//print_r($register_data);

mysqli_query($dbc," INSERT INTO `users` ($fields) VALUES  ($data)");

//mysqli_error($dbc);

}








function user_data($user_id){

	Global $dbc;

  $data=array();

  $user_id = (int)$user_id;

  

  $func_num_args=func_num_args();

 $func_get_args=func_get_args();

if($func_num_args >=1){ 

	unset($func_get_args[0]);
    
 $fields='`'.implode('`, `', $func_get_args).'`';







  $data=mysqli_query($dbc," SELECT $fields FROM `users`  WHERE `user_id` = $user_id ");
  
  //mysqli_error($dbc);

  if ($data === false) {
    die("error on mysqli_query: ". mysqli_error($dbc));
} 

$data=mysqli_fetch_assoc($data);

    


//print_r ($data);


  return $data;   


}


}




function logged_in(){
GLOBAL $dbc;

	return(isset($_SESSION['user_id'])) ? true : false;



}









function user_exists($username){
      
     GLOBAL $dbc;
	$username=sanatize($username);


$query= mysqli_query($dbc,"SELECT COUNT(`user_id`) FROM `users`  WHERE `username` = '$username' ");


 
$check= mysqli_fetch_array( $query , MYSQLI_BOTH);

return ($check[0]==1)?true:false;

}


function email_exists($email){
      
     GLOBAL $dbc;
	$email=sanatize($email);


$query= mysqli_query($dbc,"SELECT COUNT(`user_id`) FROM `users`  WHERE `email` = '$email' ");


 
$check= mysqli_fetch_array( $query , MYSQLI_BOTH);

return ($check[0]==1)?true:false;

}



function user_active($username){
      
     GLOBAL $dbc;
	$username=sanatize($username);


$query= mysqli_query($dbc,"SELECT COUNT(`user_id`) FROM `users`  WHERE `username` = '$username' AND  `active` = 1  ");


 
$check= mysqli_fetch_array( $query , MYSQLI_BOTH);

return ($check[0]==1)?true:false;

}




function user_id_from_username($username){

	 GLOBAL $dbc;
   
   $username = sanatize($username);


    $query= mysqli_query($dbc,"SELECT `user_id` FROM `users`  WHERE `username` = '$username' ");
    $check= mysqli_fetch_array( $query , MYSQLI_BOTH);

    return  $check[0]=='user_id';
     



}




function login($username , $password){

	 GLOBAL $dbc;

$user_id = user_id_from_username($username);
 
  $username = sanatize($username);
  $password = md5($password);


 $query= mysqli_query($dbc,"SELECT `user_id` FROM `users`  WHERE `username` = '$username' AND  `password` = '$password'");
 
  

//$check= mysqli_fetch_array( $query , MYSQLI_BOTH);


if(mysqli_num_rows($query) == 1)
    {
        return 0 == 1 ?  $user_id : true ; 
    }

    // no results found so return false
    return false;  

log.php

include("config/init.php");







 if(empty($_POST)===false){

$username= $_POST['username'];
$password= $_POST['password']; 

}

if(empty($username) ===true || empty($password) ===true){

 $errors[] ='Please enter a valid username and password';



} else if (user_exists($username)===false){

$errors[] ='This username does not exist. Please sign up';


}  else if (user_active($username)===false) {

   $errors[]="you have not activated your account via email";

} else { // here errors //testing username passwords ect, if all of the above statemens failed
        
         $login=login($username,$password);  

         if($login===false){

         	//$error[]= 
         	echo "That username and password combination is incorrect";


         }  else { // set username session
         	       // redirect user to home

         	        //die($login);

         	       $_SESSION['user_id']=$login;

         	       header('location:index.php');

         	       exit(); 
                  

         } 
 
} 


//print_r($errors);



 include('templates/header.php');






 

 include('templates/footer.php');

?>
               

config/init.php

<?php

session_start();



require('connect.php');
require('functions/general.php');
require('functions/users.php');





// to be accessed by every page to check errors for login



if(logged_in()===true){


	$session_user_id=$_SESSION['user_id'];

$user_data = user_data($session_user_id,'user_id','username','password','name' ,'surname' ,'email');

   //echo $user_data['name'];

if(user_active($user_data['username'])=== false){

	session_destroy();
	header('Location:index.php');
	exit();


}




} //else echo "cannot retreive data";





$errors=array();


?>

this does not echo correct username or id . no errors are displayed

<aside id="widgets">





require_once('config/init.php'); 
require_once('config/functions/users.php'); 
require_once('config/functions/general.php'); 


  ?>


<h4 class="username"> Welcome 

 <?php   echo $user_data['name'];?>   </h4>	



<div class="inner">

           <ul>
                  <li> <a href="logout.php"> Log out </a> </li>

                 <li> <a href="changepassword.php"> New password </a>   </li>

           </ul>

</div> 
          
  <?php echo mysqli_error($dbc);?>

</aside>

<?php   include('templates/footer.php');   ?>

<?php


?>

[jazzman1]

I think here you should have to return $row['user_id'] from your database table instead just true;

function logged_in(){
GLOBAL $dbc;

	return(isset($_SESSION['user_id'])) ? true : false;

}

[h1234]

 

I think here you should have to return $row['user_id'] from your database table instead just true;

function logged_in(){
GLOBAL $dbc;

	return(isset($_SESSION['user_id'])) ? true : false;

}

Thanks man but how? im new to php

[Ch0cu3r]

Which ever user successfully logs in, Your code will always return the user's data with the user_id of 1.

 

This is because your login() function does not return the users user_id but the boolean value of  true when the username and password match a record in the users table!

function login($username , $password)
{
    GLOBAL $dbc;

    $user_id = user_id_from_username($username);

    $username = sanatize($username);
    $password = md5($password);

    $query= mysqli_query($dbc,"SELECT `user_id` FROM `users`  WHERE `username` = '$username' AND  `password` = '$password'");

    if(mysqli_num_rows($query) == 1)
    {
        return 0 == 1 ?  $user_id : true;
    }

    // no results found so return false
    return false; 
}

This line will always return true

return 0 == 1 ?  $user_id : true;

You save the returned value of login() to the $_SESSION['user_id'] variable.

 

This variable is then passed to the user_data() function to get the logged in users data. You then convert the users id value to an integer.

$user_id = (int)$user_id;

Which will convert the boolean value of $user_id to the integer value of 1. So therefore the query within that function will always return the user with the user_id of 1.

$data=mysqli_query($dbc," SELECT $fields FROM `users`  WHERE `user_id` = $user_id ");

 

What you need to do is set the session data when the query successfully returns a result with a matched username/password. You should not be using user_data() function to get their data on each page request.

 

This will be your login function

function login($username , $password)
{
    GLOBAL $dbc;

    $username = sanatize($username);
    $password = md5($password);

    // get all users data from database when username/password match.
    $query= mysqli_query($dbc,"SELECT `user_id`, `username`, `name` , `surname`, `email`  FROM `users`  WHERE `username` = '$username' AND  `password` = '$password'");

    if(mysqli_num_rows($query) == 1)
    {
        // set user data to sessions
        $row = mysqli_fetch_assoc($query);
        $_SESSION['user_id']  = $row['user_id'];
        $_SESSION['username'] = $row['username'];
        $_SESSION['name']     = $row['name'];
        $_SESSION['surname']  = $row['surname'];
        $_SESSION['email']    = $row['email'];

        return true; // return true
    }

    // no results found so return false
    return false; 
}

 

To check if the user successfully logged in with the username/password you'd do

if(login($username, $password))
{
    // successfully logged in!
    
    // Session data is already reloaded with users data
    printf('<pre>%s</pre>', print_r($_SESSION, true));
}
else
{
   // did not successfully login
}

[h1234]

Which ever user successfully logs in, Your code will always return the user's data with the user_id of 1.

 

This is because your login() function does not return the users user_id but the boolean value of  true when the username and password match a record in the users table!

function login($username , $password)
{
    GLOBAL $dbc;

    $user_id = user_id_from_username($username);

    $username = sanatize($username);
    $password = md5($password);

    $query= mysqli_query($dbc,"SELECT `user_id` FROM `users`  WHERE `username` = '$username' AND  `password` = '$password'");

    if(mysqli_num_rows($query) == 1)
    {
        return 0 == 1 ?  $user_id : true;
    }

    // no results found so return false
    return false; 
}

This line will always return true

return 0 == 1 ?  $user_id : true;

You save the returned value of login() to the $_SESSION['user_id'] variable.

 

This variable is then passed to the user_data() function to get the logged in users data. You then convert the users id value to an integer.

$user_id = (int)$user_id;

Which will convert the boolean value of $user_id to the integer value of 1. So therefore the query within that function will always return the user with the user_id of 1.

$data=mysqli_query($dbc," SELECT $fields FROM `users`  WHERE `user_id` = $user_id ");

 

What you need to do is set the session data when the query successfully returns a result with a matched username/password. You should not be using user_data() function to get their data on each page request.

 

This will be your login function

function login($username , $password)
{
    GLOBAL $dbc;

    $username = sanatize($username);
    $password = md5($password);

    // get all users data from database when username/password match.
    $query= mysqli_query($dbc,"SELECT `user_id`, `username`, `name` , `surname`, `email`  FROM `users`  WHERE `username` = '$username' AND  `password` = '$password'");

    if(mysqli_num_rows($query) == 1)
    {
        // set user data to sessions
        $row = mysqli_fetch_assoc($query);
        $_SESSION['user_id']  = $row['user_id'];
        $_SESSION['username'] = $row['username'];
        $_SESSION['name']     = $row['name'];
        $_SESSION['surname']  = $row['surname'];
        $_SESSION['email']    = $row['email'];

        return true; // return true
    }

    // no results found so return false
    return false; 
}

 

To check if the user successfully logged in with the username/password you'd do

if(login($username, $password))
{
    // successfully logged in!
    
    // Session data is already reloaded with users data
    printf('<pre>%s</pre>', print_r($_SESSION, true));
}
else
{
   // did not successfully login
}

thanks but where do i place this in my init.php file?  as all i am getting is underfined variables. Is there any way to change the user_data function only to get this to work as i want to echo the username when user logs in. i hope this make sense. thanks

[Ch0cu3r]

You do not need the user_data() function any more. This has now been merged with the login() function. The login function stores the users data in the $_SESSION. 

 

Instead of using the $user_data variable to get the users data you now use $_SESSION. When you want to echo the users name, you use

 <?php echo $_SESSION['name'];?> 

Instead of $user_data['name']

[h1234]

You do not need the user_data() function any more. This has now been merged with the login() function. The login function stores the users data in the $_SESSION. 

 

Instead of using the $user_data variable to get the users data you now use $_SESSION. When you want to echo the users name, you use

 <?php echo $_SESSION['name'];?> 

Instead of $user_data['name']

 

thanks but what happens to this  functions as i use this to state what files are protected for example and this states what user can see it links to. When i use the if statement to check when user is logged in i get undefined variables for username and password.

function logged_in(){
GLOBAL $dbc;

	

       return isset($_SESSION['user_id']) ;

 



   
}

this was whats in my init.php file  i am not using the $user_data anymore but if i do then it doesnt recognise .It still doesnt echo out the name. the session is started in this file

if(logged_in()===true){


	$session_user_id=$_SESSION['user_id'];

$user_data = user_data($session_user_id,'user_id','username','password','name' ,'surname' ,'email');

   //echo $user_data['name'];

if(user_active($user_data['username'])=== false){

	session_destroy();
	header('Location:index.php');
	exit();


}




} 

you been a great help so far. thanks man

[h1234]

thanks but what happens to this  functions as i use this to state what files are protected for example and this states what user can see it links to. When i use the if statement to check when user is logged in i get undefined variables for username and password.

function logged_in(){
GLOBAL $dbc;

	

       return isset($_SESSION['user_id']) ;

 



   
}

this was whats in my init.php file  i am not using the $user_data anymore but if i do then it doesnt recognise .It still doesnt echo out the name. the session is started in this file

if(logged_in()===true){


	$session_user_id=$_SESSION['user_id'];

$user_data = user_data($session_user_id,'user_id','username','password','name' ,'surname' ,'email');

   //echo $user_data['name'];

if(user_active($user_data['username'])=== false){

	session_destroy();
	header('Location:index.php');
	exit();


}




} 

you been a great help so far. thanks man

another thing is that user_data is being used to change passwords as well. 

[Ch0cu3r]

The logged_in function should work as before, no need to modify it.

 

No need to use the user_data function as data is already in the $_SESSION variable

 

Do not use $user_data, use $_SESSION

 

init.php should be

if(logged_in() === true)
{
    $session_user_id = $_SESSION['user_id'];

    if(user_active($_SESION['username']) === false){
        session_destroy();
        header('Location:index.php');
        exit();
    }
}

 

 

another thing is that user_data is being used to change passwords as well. 

how Is the password changed?

[h1234]

The logged_in function should work as before, no need to modify it.

 

No need to use the user_data function as data is already in the $_SESSION variable

 

Do not use $user_data, use $_SESSION

 

init.php should be

if(logged_in() === true)
{
    $session_user_id = $_SESSION['user_id'];

    if(user_active($_SESION['username']) === false){
        session_destroy();
        header('Location:index.php');
        exit();
    }
}

how Is the password changed?

i just changed code and now it doesnt logged me in at all.  the code below does not work. Where must this be placed after the login function? it says i am not logged in 

if(login($username, $password))
{
    // successfully logged in!
    
    // Session data is already reloaded with users data
    printf('<pre>%s</pre>', print_r($_SESSION, true));
}
else
{
   // did not successfully login
}

if(logged_in()===true){


	$session_user_id=$_SESSION['user_id'];

$user_data = user_data($session_user_id,'user_id','username','password','name' ,'surname' ,'email');

	//$_SESSION['user_id','username','password','name' ,'surname' ,'email'];

   //echo $user_data['name'];

if(user_active($user_data['username'])=== false){

	session_destroy();
	header('Location:index.php');
	exit();


}




} //else echo "cannot retreive data";

only logs in with the old code in init.php

[Ch0cu3r]

i just changed code and now it doesnt logged me in at all.  the code below does not work. Where must this be placed after the login function? it says i am not logged in 

if(login($username, $password))
{
    // successfully logged in!
    
    // Session data is already reloaded with users data
    printf('<pre>%s</pre>', print_r($_SESSION, true));
}
else
{
   // did not successfully login
}

That code above is to replace this code in log.php

 $login=login($username,$password);  
         if($login===false){

         	//$error[]= 
         	echo "That username and password combination is incorrect";

         }  else { // set username session
         	       // redirect user to home

         	        //die($login);

         	       $_SESSION['user_id']=$login;

         	       header('location:index.php');

         	       exit(); 
         }

Replace // successfully logged in! with the code you want to run when user successfully logs in

 

Replace // did not successfully login with the code you want to run when the user does not successfully login.

 

You can remove printf('<pre>%s</pre>', print_r($_SESSION, true));. it is only there to display what is stored within the $_SESSION variable when login is successful.

 

The code in reply #9 replaces the code in init.php

[h1234]

That code above is to replace this code in log.php

 $login=login($username,$password);  
         if($login===false){

         	//$error[]= 
         	echo "That username and password combination is incorrect";

         }  else { // set username session
         	       // redirect user to home

         	        //die($login);

         	       $_SESSION['user_id']=$login;

         	       header('location:index.php');

         	       exit(); 
         }

Replace // successfully logged in! with the code you want to run when user successfully logs in

 

Replace // did not successfully login with the code you want to run when the user does not successfully login.

 

You can remove printf('<pre>%s</pre>', print_r($_SESSION, true));. it is only there to display what is stored within the $_SESSION variable when login is successful.

 

The code in reply #9 replaces the code in init.php

 

Awsome man . it seems to be working as i see the different user_id display correct within the array. but now i get this error and it does not stay logged in.

 

 

 

this is what i get in the log.php 

Notice: Undefined index: username in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 218

Notice: Undefined index: name in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 219

Notice: Undefined index: surname in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 220

Notice: Undefined index: email in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 221

Notice: Undefined index: username in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 218

Notice: Undefined index: name in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 219

Notice: Undefined index: surname in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 220

Notice: Undefined index: email in /Applications/XAMPP/xamppfiles/htdocs/php/testing/config/functions/users.php on line 221
successfully logged in!

Array
(
    [user_id] => 6
    [username] => 
    [name] => 
    [surname] => 
    [email] => 
)

[jazzman1]

Make some effort man. @Ch0cu3r did the hard part of the code for you, all you need to do is to define username, surname,name and mails variables like user_id and to redirect the page.