B_CooperA Posted November 27, 2013 Share Posted November 27, 2013 Hello, guys. I recently started to take a closer look into the world of AJAX. I'm trying to create a live search application, but for some reason it doesn't return the values from the database although it's still does something when I checked it with Googles "Inspect Element" tool. The only response I got with that tool is "This request has no responsive data available". I have two files, index.php and search.php. Underneath, I've pasted both of them. The search engine works fine without AJAX, tested that while ago. index.php <!DOCTYPE html> <html> <head> <title>Ajax Search Engine</title> <link rel="stylesheet" type="text/css" href="css/style.css" media="all" /> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#search").on("keyup", function() { var search = $("#search").val(); $.ajax({ type: "POST", url: "search.php", data: {search:search}, success: function(res) { $("#userslist").html(res); } }); }); }); </script> </head> <body> <div id="search"> <input type="text" name="search" id="search" placeholder="Search for users..."> <button type="submit" class="search-icon"><span class="magnifier"></span></button> </div> <div id="userslist"> </div> </body> </html> search.php <?php try { $conn = new PDO("mysql:host=localhost;dbname=search","root", ""); } catch (Exception $e) { $e->getMessage(); } if(isset($_POST['search']) && $_POST['search'] != "") { $stmt = $conn->prepare("SELECT * FROM users WHERE username LIKE :name "); $stmt->execute(array( ':name' => '%'.$_POST['search'].'%' )); if($stmt->rowCount() == 0) { echo "No users was found"; } else { while($data = $stmt->fetch()) { ?> <div class="user-details"> <img src="images/<?php echo $data['userimg']; ?>" class="small-img" /> <span class="username"><?php echo $data['username'];?></span> <span class="location"><?php echo $data['location'];?></span> </div> <?php } } } ?> Quote Link to comment https://forums.phpfreaks.com/topic/284317-learning-ajax-got-stucked-on-the-first-example/ Share on other sites More sharing options...
Solution requinix Posted November 27, 2013 Solution Share Posted November 27, 2013 You've got more than one element in the HTML with id=search... Quote Link to comment https://forums.phpfreaks.com/topic/284317-learning-ajax-got-stucked-on-the-first-example/#findComment-1460303 Share on other sites More sharing options...
B_CooperA Posted November 27, 2013 Author Share Posted November 27, 2013 Wow, thanks.. How negligent I was Quote Link to comment https://forums.phpfreaks.com/topic/284317-learning-ajax-got-stucked-on-the-first-example/#findComment-1460304 Share on other sites More sharing options...
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