PHP images sorting by reverse

[SteveDahdah]

I have the following code:

<?

Header("content-type: application/x-javascript");

$pathstring=pathinfo($_SERVER['PHP_SELF']);

$locationstring="http://" . $_SERVER['HTTP_HOST'].$pathstring['dirname'] . "/";



function returnimages($dirname=".") {

$pattern="(\.jpg$)|(\.jpeg$)|(\.gif$)";

$files = array();



$mostRecent=0;
$curimage=0;

if($handle = opendir($dirname)) {

while(false !== ($file = readdir($handle))){

if(eregi($pattern, $file)){

echo 'picsarray[' . $mostRecent .']="' . $file . '";';

$mostRecent++;

}

}



closedir($handle);

}

return($files);

}



echo 'var locationstring="' . $locationstring . '";';

echo 'var picsarray=new Array();';


returnimages()

?> 

I want to sort the images by reverse because This code sort pictures like this: picsarray[0]="2013-11-29 11:42:11 pm.jpg";picsarray[1]="2013-11-29 11:58:24 pm.jpg";picsarray[2]="2013-11-30 12:13:36 am.jpg";picsarray[3]="2013-11-30 12:27:46 am.jpg"

I want to sort them by reverse. Anyone can help me to fix this problem?

 

[Ch0cu3r]

Sort the picsarray in the javascript using

picsarray.reverse();

Or sort the pictures first in PHP before generating the JavaScript picsarray

function returnimages($dirname=".")
{
    $pattern="~\.(jpe?g|gif)$~";

    $files = array();

    if($handle = opendir($dirname))
    {
        while(false !== ($file = readdir($handle))){
            if(preg_match($pattern, $file)){
                $files[] = $file;
            }
        }

        closedir($handle);
    }

    // sort pics in reverse order
    rsort($files);

    // output images into javascript array
    foreach($files as $key => $pic)
    {
        echo "picsarray[$key] = '$pic'";
    }
}

[SteveDahdah]

The second code is working. But now i cant display images as a drop down menu in my html page.

 

can you help me?

[Ch0cu3r]

Add a ; after '$pic' below

 

echo "picsarray[$key] = '$pic';";

                              ^ add this

 

This could be causing a JavaScript error, which then prevents the dropdown menu from displaying.