brownbrod Posted February 17, 2014 Share Posted February 17, 2014 I have created a form to update records using the ID primary key. I am unable to use the Drop Down menu to select the record to update. I believe I have everything else correct. I would greatly appreciate your feedback. Thanks, <html> <head><meta http-equiv="Content-Type" content="text/html; charset=windows-1252"><title>New Page 1</title></head> <body><?php $connect=mysql_connect('us70tudbs001.zam.alcatel-lucent.com:3306','norab','norab') or die("Unable to Connect");@mysql_select_db('rightfirst') or die("Could not open the db"); $query="SELECT * FROM contacts";$result=mysql_query($query) or die("Query Failed : ".mysql_error()); $i=0; while($rows=mysql_fetch_array($result)){$roll[$i]=$rows['id'];$i++;}$total_elmt=count($roll);?><form method="post" action="">Select the ID No. to Update: <select name="sel"><option>Select</option><?phpfor($j=0;$j<$total_elmt;$j++){?></option><?phpecho $roll[$j];?></option><?php}?></select><br />First Name: <input name="first" type="text" /><br />Last Name: <input name="last" type="text" /><br />Phone: <input name="phone" type="text" /><br /><input name="submit" type="submit" value="Updated"/><br /><input name="reset" type="reset" value="Reset" /></form> <?phpif(isset($_POST['submit'])){$value=$_POST['sel'];$first=$_POST['first'];$last=$_POST['last'];$phone=$_POST['phone']; $query2 = "UPDATE contacts SETfirst='$first',last='$last',phone='$phone' WHEREid='$value'";$result2=mysql_query($query2) or die("Query Failed :".mysql_error());echo "Successfully Updated";}?><p align=right><a href="view.php">VIEW RECORDS</a></p> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/ Share on other sites More sharing options...
jazzman1 Posted February 17, 2014 Share Posted February 17, 2014 (edited) I cannot see where the value attribute of select option tag is? Please, use the code [ code ] tags when providing code. Edited February 17, 2014 by jazzman1 Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469316 Share on other sites More sharing options...
tazmith Posted February 18, 2014 Share Posted February 18, 2014 (edited) <?php /* * PDO version. */ $host = 'host'; $dbname = 'db_name'; $user = 'db_user'; $pass = 'db_pass'; try { $dbh = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass); } catch(PDOException $e) { echo $e->getMessage(); } echo '<form method="POST">Select id to edit: <select name="id">'; $query = $dbh->query('SELECT id FROM contacts ORDER BY id ASC'); foreach ($query->fetchAll(PDO::FETCH_ASSOC) as $row) { echo '<option value="'.$row['id'].'">'.$row['id'].'</option>'; } echo '</select>'; echo '<br /><div> First Name: <input name="first" type="text" /><br />'; echo '<input type="submit" name="submit" id="submit" value="Submit" /> </form>'; if (isset($_POST['submit'])) { echo '<br />Editing ID: '.htmlspecialchars($_POST['id'],ENT_QUOTES). ''; if (empty($_POST['first']) === false) { //firstname has been edited, lets update. $update_query = $dbh->prepare('UPDATE contacts SET ' . 'first=:first WHERE ' . 'id=:id '); $update_query->bindParam(':first', $_POST['first']); $update_query->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $update_query->execute(); echo '<br />Updated firstname to '.htmlspecialchars($_POST['first'],ENT_QUOTES).''; } } /* /* * mysql_ version. */ echo '<form method="POST">Select id to edit: <select name="id" id="ids">'; $query = "SELECT id FROM contacts ORDER BY id ASC"; $result = mysql_query($query) or die ( mysql_error ()); while ($row = mysql_fetch_array($result,MYSQL_ASSOC)) { echo '<option value="'.$row['id'].'">'.$row['id'].'</option>'; } echo '</select>'; echo '<br /><div> First Name: <input name="first" type="text" /><br />'; echo '<input type="submit" name="submit" id="submit" value="Submit" /> </form>'; if (isset($_POST['submit'])) { echo '<br /><br />Editing id: ' .htmlspecialchars($_POST['id'],ENT_QUOTES). ''; if (empty($_POST['first']) === false) { $id = (int)$_POST['id']; $firstname = mysql_real_escape_string($_POST['first']); $update_query = "UPDATE contacts SET first = '$firstname' WHERE id = '$id'"); $update_result = mysql_query($update_result) or die ( mysql_error ()); echo '<br />Updated firstname to '.htmlspecialchars($_POST['first'],ENT_QUOTES).''; } } ?> Edited February 18, 2014 by tazmith Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469349 Share on other sites More sharing options...
brownbrod Posted February 18, 2014 Author Share Posted February 18, 2014 This worked perfectly. Now. is there a way to show what the old value is before you udpate it? What I have seen looks to be very complexed. For example: Let's say I am updating ID 5 and I want to make sure it belongs to Catherine ('first'). How would I do that? Thanks so much for your help. Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469433 Share on other sites More sharing options...
Ch0cu3r Posted February 18, 2014 Share Posted February 18, 2014 (edited) Better option would be to populate the select field with the users first name, setting the id as the value for that option, eg echo '<form method="POST">Select name to edit: <select name="id">'; $query = $dbh->query('SELECT id, first FROM contacts ORDER BY first ASC'); foreach ($query->fetchAll(PDO::FETCH_ASSOC) as $row) { // set record id as value, and first name as option label echo '<option value="'.$row['id'].'">'.$row['first'].'</option>'; } echo '</select>'; Now you'd select the the name you want to edit, and then when the form is submitted the name will be updated to whatever you entered into the name field. Edited February 18, 2014 by Ch0cu3r Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469442 Share on other sites More sharing options...
brownbrod Posted February 18, 2014 Author Share Posted February 18, 2014 I need to update the Name using the "ID" that is associated with the name. So what I was wondering is can I view what is already in the "first" field before it is changed? Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469445 Share on other sites More sharing options...
Ch0cu3r Posted February 18, 2014 Share Posted February 18, 2014 That is what my code change does. It sets the Name as the label for the select input. It still sends the id associated with that name when form is submitted. Live Example http://phpfiddle.org/lite/code/c71-1p4 (click the run button, right hand side when page loads) Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469446 Share on other sites More sharing options...
tazmith Posted February 18, 2014 Share Posted February 18, 2014 I need to update the Name using the "ID" that is associated with the name. So what I was wondering is can I view what is already in the "first" field before it is changed? if you wanted to you could have a drop down with the ID'S, and submit leading to a page like update.php?updateid=userid which will than show the input fields for first, last, ect. And than on that submit, create the POST submit. Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469451 Share on other sites More sharing options...
Solution tazmith Posted February 19, 2014 Solution Share Posted February 19, 2014 Hope this helps you. It's basic, this can be done in many ways, but here's a re-vamped version of what I did in my 1st post. Note: I wen't with the PDO version, because mysql_ is just bad practice in my opinion, but that's only my opinion <?php $host = 'host'; $dbname = 'db_name'; $user = 'db_user'; $pass = 'db_pass'; try { $dbh = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass); } catch(PDOException $e) { echo $e->getMessage(); } if (!isset($_POST['selectid']) && !isset($_POST['submit'])) { echo '<form method="POST">Select ID to edit: <select name="id">'; $query = $dbh->query('SELECT id FROM contacts ORDER BY id ASC'); foreach ($query->fetchAll(PDO::FETCH_ASSOC) as $row) { echo '<option value="'.$row['id'].'">'.$row['id'].'</option>'; } echo '</select>'; echo '<input type="submit" name="selectid" id="selectid" value="Submit" /> </form>'; } //selecting the id. if (isset($_POST['selectid'])) { $query = $dbh->prepare('SELECT first,last,id FROM contacts WHERE ' . 'id=:id '); $query->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $query->execute(); $row = $query->fetch(PDO::FETCH_ASSOC); $count = $query->rowCount(); //incase of POST data manipulation if ($count < 1) { die('Error: User does not exist!'); } echo 'Viewing ID: '.$row['id'].' Firstname: '.$row['first'].''; //the form. echo '<br /><br /> <form method="POST"><div> First Name: <input type="text" name="first" value="'.$row['first'].'" /><br /> Last Name: <input type="text" name="last" value="'.$row['last'].'" /><br /> <input type="hidden" name="id" value="'.$row['id'].'" /> <input type="submit" name="submit" id="submit" value="Submit" />'; echo '<br /><br /><a href="pagehere.php">go back</a>'; } //submitting. if (isset($_POST['submit'])) { if (empty($_POST['first']) === false) { //update firstname, since it was updated. $firstname_update = $dbh->prepare('UPDATE contacts SET ' . 'first=:first WHERE ' . 'id=:id '); $firstname_update->bindParam(':firstname', $_POST['first']); $firstname_update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $firstname_update->execute(); //echo if wanted. echo 'Updating Firstname of ID: '.htmlspecialchars($_POST['id'],ENT_QUOTES).' to '.htmlspecialchars($_POST['first'],ENT_QUOTES).''; //just continue onward for lastname, phone, whatever you wan't really. echo '<br /><br /><a href="pagehere.php">go back</a>'; } } ?> Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469455 Share on other sites More sharing options...
brownbrod Posted February 19, 2014 Author Share Posted February 19, 2014 This is what I needed. Thanks for your guidance. I really appreciate it. Have a great day! Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469537 Share on other sites More sharing options...
tazmith Posted February 19, 2014 Share Posted February 19, 2014 No problem, glad I could help. Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469581 Share on other sites More sharing options...
brownbrod Posted February 20, 2014 Author Share Posted February 20, 2014 One more question. Using this formula can I update two fields in one submit? For example: //update firstname, since it was updated. $firstname_update = $dbh->prepare('UPDATE contacts SET ' . 'first=:first WHERE ' . 'id=:id '); $firstname_update->bindParam(':firstname', $_POST['first']); $firstname_update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $firstname_update->execute(); //update lastname, since it was updated. $lastname_update = $dbh->prepare('UPDATE contacts SET ' . last=:lastWHERE ' . 'id=:id '); $lastname_update->bindParam(':lastname, $_POST[last]); $lastname_update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $lastname_update->execute(); So when I click "SUBMIT" it updates both? This is just an example. I greatly appreciate your feedback. Thanks so much!!! Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469773 Share on other sites More sharing options...
tazmith Posted February 20, 2014 Share Posted February 20, 2014 you can run everything through 1 update if you wanted. You don't need to use if (empty($_POST['first']) === false) { } instead you could just update everything on if (isset($_POST['submit'])) { //run query that updates all $_POST data here. } Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469775 Share on other sites More sharing options...
Ch0cu3r Posted February 21, 2014 Share Posted February 21, 2014 (edited) One more question. Using this formula can I update two fields in one submit? For example: //update firstname, since it was updated. $firstname_update = $dbh->prepare('UPDATE contacts SET ' . 'first=:first WHERE ' . 'id=:id '); $firstname_update->bindParam(':firstname', $_POST['first']); $firstname_update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $firstname_update->execute(); //update lastname, since it was updated. $lastname_update = $dbh->prepare('UPDATE contacts SET ' . last=:lastWHERE ' . 'id=:id '); $lastname_update->bindParam(':lastname, $_POST[last]); $lastname_update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $lastname_update->execute(); So when I click "SUBMIT" it updates both? This is just an example. I greatly appreciate your feedback. Thanks so much!!! Yes, you can update the lastname in a separate query. But it is more effeicent to update the firstname, and lastname within one query, using //update firstname and lastname fields $update = $dbh->prepare('UPDATE contacts SET first=:firstname, last=:lastname WHERE id=:id '); /* the update query */ $update->bindParam(':firstname', $_POST['first']); /* the firstname field */ $update->bindParam(':lastname', $_POST['last']); /* the lastname field */ $update->bindParam(':id', $_POST['id'], PDO::PARAM_INT); $update->execute(); Edited February 21, 2014 by Ch0cu3r Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469826 Share on other sites More sharing options...
brownbrod Posted February 21, 2014 Author Share Posted February 21, 2014 As always!! Thank you for your help. You are awesome!! Quote Link to comment https://forums.phpfreaks.com/topic/286276-update-form-using-php/#findComment-1469857 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.