header location

[arunpatal]

When i don't use header then javascript runs

but after adding header (below javascript) javascript is not working

if(isset($_POST["update_cart"])){
		
		foreach($_POST["quantity"] as $pid => $qty):
		
			@array_splice($_SESSION["my_cart"][$pid] = $qty);
			
			if ($_SESSION["my_cart"][$pid] < 1 ){ unset ($_SESSION["my_cart"][$pid]);} 
			
			elseif ($_SESSION["my_cart"][$pid] > 10){ $_SESSION["my_cart"][$pid] = 10; 
			echo "<script> alert('quantity cannot be more then 10') </script>"; };
			
		endforeach;
		
		header("location:" . $_SERVER["PHP_SELF"]);
		
	};

[ginerjm]

You really don't want to use JS to issue an error message from within your php script.  That's why header doesn't work, which you would probably know if you had error checking turned on.  Design your script to re-issue your page with an error message area that you can then populate with messages and re-display the page so that the user can make corrections.

[r3wt]

if you want to redirect without issuing the die function or exit function, you can use the following which i use on my website to keep it from glitching and continue so i can process the error and continue executing code later if i need to.

 

if( /* CONDITIONS HERE */){

echo '<meta http-equiv="refresh" content="0; URL=http://example.com/page.php">';

}

 

for example if you want to save some time by passing the error to the next page, or if you need to regenerate some form data:

$error = false;

$errors = array();

 

//statement that failed

 

if(hash('sha512',$enteredpass . $salt) != $storedpass){

$error = true;

 

}

 

if($error === true){

$error_id = "somerandomlongstring";

//generate error message

foreach($error as $errors[]) {

 

$message = "Error: username or password invalid";

$user = $_POST["user"];

$ip = getIp();

$query = mysql_query("INSERT...");

}

echo '<meta http-equiv="refresh" content="0; URL=index.php?page=login&error=".$error_id."">';

}

 

 

then on the page you do a query to get the error string

 

if(isset($_GET["error"])){

 

//query the results.

$sql = mysql_query....;

$num_rows = mysql_num_rows($sql);

 

for($i = 0; $i < $num_rows; $i++){

$errors = array();

$error[$i] = mysql_result($sql,$i,"message");

 

echo $error[$i]."</br>";

}