JezLisle Posted April 2, 2014 Share Posted April 2, 2014 (edited) I'm trying to refresh a data input into an INPUT through a form and then SUBMIT this to the database to return it as a table on the same page. I want it to do this without showing the refresh of the page. This is what I have currently. When I put data into any of the INPUT fields and click SUBMIT nothing happens and nothing shows for an error. <?php session_start(); error_reporting (E_ALL); require '../core/cnn.php'; if(isset($_POST['submitsearchprojno'])) { $searchprojno = $_POST["searchprojno"]; } if(isset($_POST['submitsearchadd'])) { $searchaddress = $_POST["searchaddress"]; } if(isset($_POST['submitsearchpc'])) { $searchpostcode = $_POST["searchpostcode"]; } $searchpostcode = mysql_real_escape_string($searchpostcode); $searchaddress = mysql_real_escape_string($searchaddress); $searchprojno = mysql_real_escape_string($searchprojno); ?> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true"></button> <h4 class="modal-title">Search Projects</h4> </div> <div class="modal-body"> <form class="modal-form" id="searchform" name="searchform" action="" method="post"> <div class="form-group"> <label class="col-md-4 control-label">Project Number</label> <div class="col-md-6"> <input type="text" class="form-control input-inline input-medium" name="searchprojno" id="searchprojno" placeholder="Enter Project Number"> </div> <button type="submit" class="btn blue" id="submitsearchprojno" name="submitsearchprojno" >Search <i class="m-icon-swapright m-icon-white"></i></button> </div> <div class="form-group"> <label class="col-md-4 control-label">Address</label> <div class="col-md-6"> <input type="text" class="form-control input-inline input-medium" name="searchaddress" id="searchaddress" placeholder="Enter Address"> </div> <button type="submit" class="btn blue" id="submitsearchadd" name="submitsearchadd" >Search <i class="m-icon-swapright m-icon-white"></i></button> </div> <div class="form-group"> <label class="col-md-4 control-label">Postcode</label> <div class="col-md-6"> <input type="text" class="form-control input-inline input-medium" name="searchpostcode" id="searchpostcode" placeholder="Enter Postcode"> </div> <button type="submit" class="btn blue" id="submitsearchpc" name="submitsearchpc" >Search <i class="m-icon-swapright m-icon-white"></i></button> </div> <div class="form-group"> <div class="col-md-12"> <div class="table-responsive"> <table class="table table-striped table-bordered table-advance table-hover"> <thead> <tr> <th class="col-md-9"><i class="fa fa-list-alt"></i> Address</th> <th class="col-md-3"></th> </tr> </thead> <tbody> <tr> <?php $searchrs = mysql_query("SELECT ProjectNo, CONCAT(COALESCE(HouseNoName, ''), ' ', COALESCE(StreetName, ''), ' ', COALESCE(TownOrCity, ''), ' ', COALESCE(Postcode, '')) AS Display, PropID, AreaID, AWGMember, Householder, HouseNoName, StreetName, TownOrCity, Postcode, ContactTelephone, AlternatePhone, Email, PropertyTenure, PropertyNotes FROM prop_property WHERE IsActive = 1 AND (Postcode = '".$searchpostcode."' OR StreetName = '".$searchaddress."' OR ProjectNo = '".$searchprojno."') ") or die(mysql_error()); $checkrs = mysql_query("SELECT * FROM prop_property WHERE IsActive = 0"); if(!mysql_num_rows($checkrs) > 0) { echo '<td> No record found!</td><td></td>'; } else { while ($results = mysql_fetch_array($searchrs)) { echo ' <td id="displayadd">'.$results['Display'].'</td> <td> <form action="../jobdetails.php" method="post"> <input type="hidden" name="searchhouse" value=" '.$results['HouseNoName'].'" > <input type="hidden" name="searchstreet" value=" '.$results['StreetName'].'" > <input type="hidden" name="searchtown" value=" '.$results['TownOrCity'].'" > <input type="hidden" name="searchpostcode" value=" '.$results['Postcode'].'" > <input type="hidden" name="searchpropid" value=" '.$results['PropID'].'" > <input type="hidden" name="searchprojectno" value=" '.$results['ProjectNo'].'" > <button type="submit" class="btn default btn-xs blue-stripe" id="viewsearch" name="viewsearch">View Address</button> </form> </td>'; } }?> </tr> </tbody> </table> </div> </div> </div> </form> <div class="modal-footer right"> <button type="button" data-dismiss="modal" class="btn default">Cancel</button> </div> <script type="text/javascript"> $(function(){ $('#searchform').on('submit', function(e){ e.preventDefault(); //alert($('#searchpostcode').val()) $.post('includes/jobdetailssearch.php', $('#searchform').serialize(), function(data, status){ $('.table-responsive #displayadd').html(data.Display); //$("#table-responsive td").last().append(data); console.log("done"); }).fail(function () { console.log("fail"); }); }); }); </script> How can I get it to POST the INPUT to the database and return in the table? Edited April 2, 2014 by JezLisle Quote Link to comment Share on other sites More sharing options...
JezLisle Posted April 2, 2014 Author Share Posted April 2, 2014 I've amended the code above to show. If the console log shows as done or fail depending on what happens when `SUBMIT` button is pressed. Why would the table not show? Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.