Dynamic Fields js/php to MySql need to submit dynamically to the database

jungle · August 23, 2014

I can not get the values from the javascript add row to go dynamically as a row into MySql only the form values show up as the form below as one row. I made it as an array, but no such luck, I have tried this code around a multitude of ways. I don't know what I am doing wrong, kindly write out the correct way.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Dynamic Fields js/php to MySql need to submit dynamically to the database</title>
<?php
require ('database.php');
?>
<script type="text/javascript">
var counter     =     1;
var collector     =     "";

function addfields(indx)
{
   var tbl = document.getElementById('table_id');
   var newtr = document.createElement('tr');
   counter = counter + indx;

   newtr.setAttribute('id','tr'+counter);

   newtr.innerHTML = '<td><input type="checkbox" name="checkb'+counter+'" id="checkb'+counter+'" value="'+counter+'" onclick="checkme('+counter+')"></td><td><input type="text" name="text1[]"></td><td><textarea name="textarea1[]"></textarea></td>';

   tbl.appendChild(newtr);
}

function checkme(dx)
{
    collector += dx+",";
}

function deletetherow(indx)
{
   var col = collector.split(",");

   for (var i = 0; i < col.length; i++)
   {
    var remvelem = document.getElementById('tr'+col);
    var chckbx = document.getElementById("checkb"+col);
    if(remvelem && chckbx.checked)
    {
     var tbl = document.getElementById('table_id');
    tbl.removeChild(remvelem);
   }
   }
}
</script>
</head>
<body>
<form enctype="multipart/form-data" id="1" style="background-color:#ffffff;" action="<?php echo $_SERVER['PHP_SELF']; ?>"></form>
<table id="table_id" >
   <tr id="tr1" class="trmain">
   <td>
   </td>
    <td>
    <input type="text" name="text1[]">
  </td>
    <td>
   <textarea name="textarea1[]"></textarea>
     </td>
   </tr>
</table>
<input type="button" value="Add" onClick="addfields(1);" />
<input type="button" value="Delete" onClick="deletetherow()" />
<input type="submit" value="Send" id="submit" name="submit"/>

<?php
if(isset($_POST['submit'])) {
for ($i=0; $i < count($_POST['text1']); $i++ )
{
$ced = stripslashes($_POST['text1'][$i]);
$erg = stripslashes($_POST['textarea1'][$i]);
}

$bnt = mysql_query("INSERT INTO tablename (first, second) VALUES ('$ced', '$erg')")or die('Error: '. mysql_error() );
$result = mysql_query($bnt);
}

?>

</body>
</html>

CroNiX · August 23, 2014

Because you only tell it to insert 2 values:

$bnt = mysql_query("INSERT INTO tablename (first, second) VALUES ('$ced', '$erg')")or die('Error: '. mysql_error() );
$result = mysql_query($bnt);

That should probably be in your loop where you are retrieving $ced and $erg from $_POST.

CroNiX · August 23, 2014

PS in the future please post code between [ code] //code here [ /code] tags

ginerjm · August 24, 2014

Since this is a multi-post I'll let you get my answer from your other site posting. Same problem - same answer.

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Dynamic Fields js/php to MySql need to submit dynamically to the database

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