manjumadhav93 Posted September 18, 2014 Share Posted September 18, 2014 As a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html><head></head><body><?phperror_reporting(E_ALL ^ E_DEPRECATED);include 'connect.php' ;$tbl_name="projects";$sql="SELECT project_name FROM $tbl_name ";$result=mysql_query($sql);if($result === FALSE) { die(mysql_error());}?><form name="resources" action="hourssubmit.php" method="post" ><?phpecho "<select name='project_name'>";while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>";}echo "</select>";?></form></body></html> Quote Link to comment Share on other sites More sharing options...
Barand Posted September 18, 2014 Share Posted September 18, 2014 Add a submit button to you form. When user clicks it, it will post the selected project_name to hourssubmit.php where you can access it with $_POST['project_name'] Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.