bravo14 Posted September 27, 2014 Share Posted September 27, 2014 Hi all Going to try and explain this as best as I can. I currently have a query that sorts a list of records by number of points, then wins, 2nd places, 3rd places etc, the query is as follows SELECT COUNT( `points` ) AS `rides`, SUM( `points` ) AS `pts`, SUM(IF(`points`=3,1,0)) AS `wins`, SUM(IF(`points`=2,1,0)) AS `2`, SUM(IF(`points`=1,1,0)) AS `1`, SUM(IF(`points`=0,1,0)) AS `0`, rider_name FROM tbl_heat WHERE card_id = 38 GROUP BY `rider_name` ORDER BY pts DESC, wins desc, `2` desc, `1` desc, `0` desc LIMIT 8 this query has resulted in this result '5','15','5','0','0','0','Jaroslaw Hampel' '5','11','3','1','0','1','Greg Hancock' '5','11','2','2','1','0','Andreas Jonsson' '5','11','2','2','1','0','Matej Zagar' '5','10','2','2','0','1','Chris Holder' '5','9','1','3','0','1','Fredrik Lindgren' '5','8','2','0','2','1','Krzystof Kasprzak' '5','7','1','2','0','2','Tai Woffinden' What I need to do is if all of these fields are the same for multiple rows I need to sort those by their result in the same heat. I have a table called tbl_heat, and it contains the following fields card_id, heat, rider_name, points So where card_id and heat are the same I need to find which out of the riders on equal points etc scored the most in that heat. for example in the example above Matej Zagar and Andreas Jonsson would be the other way round based on their heat result. Hope that makes sense. Let me know if you need me to clarify any of this, hard one to try and explain. Quote Link to comment Share on other sites More sharing options...
requinix Posted September 27, 2014 Share Posted September 27, 2014 JOIN that heat table in and add the heat column as the last thing to sort by. Quote Link to comment Share on other sites More sharing options...
bravo14 Posted September 27, 2014 Author Share Posted September 27, 2014 The data is already coming from tbl_heat, and only need to sort it by this if everything else is the same, really struggling with this Quote Link to comment Share on other sites More sharing options...
requinix Posted September 27, 2014 Share Posted September 27, 2014 Ah, I thought you needed another join... Right, and ORDER BY pts DESC, wins desc, `2` desc, `1` desc, `0` desc, heat asc(maybe heat desc, don't know the values) will do exactly that. Sorting goes left to right in that list until the values don't match, so if pts, wins, 2, 1, and 0 all match then it'll end up sorting by heat; if they don't then heat doesn't matter because one of those others determined the sort order. Quote Link to comment Share on other sites More sharing options...
bravo14 Posted September 28, 2014 Author Share Posted September 28, 2014 I have had a go and come up with the following query SELECT COUNT( `points` ) AS `rides`, SUM( `points` ) AS `pts`, SUM(IF(`points`=3,1,0)) AS `wins`, SUM(IF(`points`=2,1,0)) AS `2`, SUM(IF(`points`=1,1,0)) AS `1`, SUM(IF(`points`=0,1,0)) AS `0`, rider_name FROM tbl_heat WHERE card_id = 38 GROUP BY `rider_name` ORDER BY pts DESC, wins desc, `2` desc, `1` desc, `0` desc, (select * from tbl_heat a, tbl_heat b WHERE a.heat = b.heat AND a.card_id= 38 order by points desc) LIMIT 8 However I am not getting any result at all Quote Link to comment Share on other sites More sharing options...
Barand Posted September 28, 2014 Share Posted September 28, 2014 You cannot put a table subquery in the order by clause, only single value expressions. From the MySQL manual Identifiers may begin with a digit but unless quoted may not consist solely of digits. Bad idea to use those single digit names anyway, even if they they are quoted. Is this what you want? SELECT COUNT( points ) AS rides , SUM( a.points ) AS pts , SUM(IF(a.points=3,1,0)) AS wins , SUM(IF(a.points=2,1,0)) AS p2 , SUM(IF(a.points=1,1,0)) AS p1 , SUM(IF(a.points=0,1,0)) AS p0 , rider_name , b.points as cardpoints FROM tbl_heat a JOIN tbl_heat b USING (heat, card_id, rider_name) WHERE a.card_id = 38 GROUP BY a.rider_name ORDER BY pts DESC, wins desc, p2 desc, p1 desc, p0 desc, cardpoints desc LIMIT 8 Quote Link to comment Share on other sites More sharing options...
bravo14 Posted September 30, 2014 Author Share Posted September 30, 2014 That seems to be right, thanks for your help Quote Link to comment Share on other sites More sharing options...
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