ace2go Posted April 24, 2015 Share Posted April 24, 2015 I have the following code to pass the $id value(integer) : $id = null; if ( !empty($_GET['id'])) { $id = $_REQUEST['id']; } if ( null==$id ) { header("Location: customers.php"); } Passes successfully according to this code in the body : <?php print_r($_GET); if($_GET["id"] === "") echo "a is an empty string\n"; if($_GET["id"] === false) echo "a is false\n"; if($_GET["id"] === null) echo "a is null\n"; if(isset($_GET["id"])) echo "a is set\n"; if(!empty($_GET["id"])) echo "a is not empty"; ?> This code tries to insert data into a workorder table : if ($valid) { $pdo = Database::connect(); $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $sql = "INSERT INTO workorder (name, date, installer, salesman, category, status) values('$id', ?, ?, ?, ?, ?);"; $q = $pdo->prepare($sql); $q->execute(array($date,$installer,$salesman,$category,$status)); Database::disconnect(); header("Location: workorders.php"); } Breakdown : the $date, $installer, $salesman, $category, $status are retrieved from the form(and inserted fine), the $id is called from a prior page, gets a correct value, but is not accepted into the table. Does anyone have any ideas as to why that is? Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/ Share on other sites More sharing options...
maxxd Posted April 24, 2015 Share Posted April 24, 2015 You're mixing and matching SQL approaches. Replace this bit: $sql = "INSERT INTO workorder (name, date, installer, salesman, category, status) values('$id', ?, ?, ?, ?, ?);"; $q = $pdo->prepare($sql); $q->execute(array($date,$installer,$salesman,$category,$status)); with this: $sql = "INSERT INTO workorder (name, date, installer, salesman, category, status) values(?, ?, ?, ?, ?, ?);"; $q = $pdo->prepare($sql); $q->execute(array($id,$date,$installer,$salesman,$category,$status)); And it should work. As an aside, why are you checking the id value in _GET and then assigning it from _REQUEST? If somehow there's an 'id' index in both _GET and _POST, one of them is going to overwrite the other. If the value is set in _GET, pull it from _GET. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509832 Share on other sites More sharing options...
ace2go Posted April 24, 2015 Author Share Posted April 24, 2015 @maxxd How do I do this? the values in the array are from form fields that the user sends upon clicking the "submit" button. $id is an integer called from a prior page. I tried your code, and it does not even insert the array. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509838 Share on other sites More sharing options...
cyberRobot Posted April 24, 2015 Share Posted April 24, 2015 Is the code to test the existence of $_GET['id'] and set $id in the same script as the PDO query? Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509843 Share on other sites More sharing options...
ace2go Posted April 24, 2015 Author Share Posted April 24, 2015 I can see the existence of $_GET['id'], the code I need is to set $id in the same script as the PDO query, that is already calling the other values from a form Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509846 Share on other sites More sharing options...
maxxd Posted April 24, 2015 Share Posted April 24, 2015 I can see the existence of $_GET['id'], the code I need is to set $id in the same script as the PDO query, that is already calling the other values from a form I think I see what you're saying now. *I think*. So, you're saying the initial two blocks of code in your original post are on the page with the form output, and the third block of code is on the processing page (the value of the form action property), correct? My question is, where in the script are $date, $installer, $salesman, $category, and $status set and how? Are the values passed from the form via _POST or _GET? The id value should be in there, assuming it's in the form somewhere (this is usually done with a hidden field in the form itself or pulled directly from a session variable). Perhaps it would help if you posted a bit more code, like the form itself and the code before the "if($valid){" line. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509849 Share on other sites More sharing options...
ace2go Posted April 24, 2015 Author Share Posted April 24, 2015 (edited) my code as of yet : <?php require 'database.php'; $id = null; if ( !empty($_GET['id'])) { $id = $_REQUEST['id']; } if ( null==$id ) { header("Location: customers.php"); } if ( !empty($_POST)) { // keep track validation $ $dateError = null; $installerError = null; $salesmanError = null; $categoryError = null; $statusError = null; // keep track post values $id = $POST['name']; $date = $_POST['date']; $installer = $_POST['installer']; $salesman = $_POST['salesman']; $category = $_POST['category']; $status = $_POST['status']; // validate input $valid = true; if (empty($date)) { $dateError = 'Please enter Date'; $valid = false; } if (empty($installer)) { $installerError = 'Please enter Installer'; $valid = false; } if (empty($salesman)) { $salesmanError = 'Please enter Salesman'; $valid = false; } if (empty($category)) { $categoryError = 'Please enter Category'; $valid = false; } if (empty($status)) { $statusError = 'Please enter Status'; $valid = false; } // insert data if ($valid) { $pdo = Database::connect(); $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $sql = "INSERT INTO workorder (name, date, installer, salesman, category, status) values($id, ?, ?, ?, ?, ?);"; $q = $pdo->prepare($sql); $q->execute(array($date,$installer,$salesman,$category,$status)); Database::disconnect(); header("Location: workorders.php"); } } ?> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <link href="css/bootstrap.min.css" rel="stylesheet"> <script src="js/bootstrap.min.js"></script> </head> <body> <div class="container"> <div class="span10 offset1"> <div class="row"> <h3>Create a Workorder</h3> <?php print_r($_GET); if($_GET["id"] === "") echo "a is an empty string\n"; if($_GET["id"] === false) echo "a is false\n"; if($_GET["id"] === null) echo "a is null\n"; if(isset($_GET["id"])) echo "a is set\n"; if(!empty($_GET["id"])) echo "a is not empty"; ?> </div> <form class="form-horizontal" action="createworkorder.php" method="post"> <div class="control-group <?php echo !empty($dateError)?'error':'';?>"> <label class="control-label">Date</label> <div class="controls"> <input name="date" type="text" placeholder="Date" value="<?php echo !empty($date)?$date:'';?>"> <?php if (!empty($dateError)): ?> <span class="help-inline"><?php echo $dateError;?></span> <?php endif; ?> </div> </div> <div class="control-group <?php echo !empty($installerError)?'error':'';?>"> <label class="control-label">Installer</label> <div class="controls"> <input name="installer" type="text" placeholder="Installer" value="<?php echo !empty($installer)?$installer:'';?>"> <?php if (!empty($installerError)): ?> <span class="help-inline"><?php echo $installerError;?></span> <?php endif;?> </div> </div> <div class="control-group <?php echo !empty($salesmanError)?'error':'';?>"> <label class="control-label">Salesman</label> <div class="controls"> <input name="salesman" type="text" placeholder="Salesman" value="<?php echo !empty($salesman)?$salesman:'';?>"> <?php if (!empty($salesmanError)): ?> <span class="help-inline"><?php echo $salesmanError;?></span> <?php endif;?> </div> </div> <div class="control-group <?php echo !empty($categoryError)?'error':'';?>"> <label class="control-label">Category</label> <div class="controls"> <input name="category" type="text" placeholder="Category" value="<?php echo !empty($category)?$category:'';?>"> <?php if (!empty($categoryError)): ?> <span class="help-inline"><?php echo $categoryError;?></span> <?php endif; ?> </div> </div> <div class="control-group <?php echo !empty($statusError)?'error':'';?>"> <label class="control-label">Status</label> <div class="controls"> <input name="status" type="text" placeholder="Status" value="<?php echo !empty($status)?$status:'';?>"> <?php if (!empty($statusError)): ?> <span class="help-inline"><?php echo $statusError;?></span> <?php endif; ?> </div> </div> <div class="form-actions"> <button type="submit" class="btn btn-success">Create</button> <a class="btn" href="workorders.php">Back</a> </div> </form> </div> </div> <!-- /container --> </body> </html> Edited April 24, 2015 by ace2go Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509851 Share on other sites More sharing options...
cyberRobot Posted April 24, 2015 Share Posted April 24, 2015 It looks like you might be overriding $id here: $id = $POST['name']; Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509854 Share on other sites More sharing options...
cyberRobot Posted April 24, 2015 Share Posted April 24, 2015 Just to clarify, is the code shown in Reply 7 in a page called "createworkorder.php"? Also, is there a step before the user fills out the form? Does that step pass a GET variable called "id"? Note that if you're trying to pass the ID along with the form submission, you need to include it in the form somehow. You could, for example, add a hidden form field where $id / $_GET['id'] is the value. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509856 Share on other sites More sharing options...
ace2go Posted April 24, 2015 Author Share Posted April 24, 2015 (edited) how do I add that hidden form field? If I pass it along with the form results(in the form), how do I retain the value that was presented from the other page? @cyberRobot : Yes, the page is called "createworkorder.php", the values are passed from a page called "customers.php" Edited April 24, 2015 by ace2go Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509857 Share on other sites More sharing options...
Solution cyberRobot Posted April 24, 2015 Solution Share Posted April 24, 2015 how do I add that hidden form field? If I pass it along with the form results(in the form), how do I retain the value that was presented from the other page? Basically, you would add something like this: <input type="hidden" name="name" value="<?php echo htmlentities($id); ?>"> <div class="form-actions"> <button type="submit" class="btn btn-success">Create</button> <a class="btn" href="workorders.php">Back</a> </div> </form> Note: with the hidden field added, you'll need to modify the code for setting $id to something like this: <?php //... if(!empty($_GET['id'])) { $id = $_GET['id']; } elseif(!empty($_POST['id'])) { $id = $_POST['id']; } else { $id = null; } //... ?> That way the header() function doesn't get triggered. You'll also need to get rid of the following line so you're not overwriting $id: $id = $POST['name']; Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509860 Share on other sites More sharing options...
maxxd Posted April 24, 2015 Share Posted April 24, 2015 OK - there's a couple things I see right off the bat. First, your form doesn't have fields named 'name' or 'id', so those aren't getting passed via $_POST. You're checking $_GET['id'], then assigning $_REQUEST['id'] to $id, then overwriting that value with an apparently non-existent value: $_POST['name']. Where you've got the output checks for $_GET['id'] right before your form, add the following: print(empty($id) ? "\$id is empty or null" : "This is \$id: {$id}"); and that should output '$id is empty or null'. You're submitting the form to the same page via $_POST. Because you've specifically given the form an 'action' parameter, that means any $_GET variables aren't being carried over - check the location bar before and after you hit the submit button. You'll need to create a hidden input field and assign the value of 'id' to that field. Right after your opening form tag, insert this: <input type='hidden' name='id' value='<?= htmlentities($_GET['id']); ?>' /> Assuming that there's a value in $_GET['id'], when you submit the form from that page, you can access the value using $id = $_POST['id']; Now, if you omit the 'action' parameter of the form, it'll post to itself by default - the interesting thing here is that it means the URL will still be intact including your $_GET variables. So, if you remove the "action='createworkorder.php'" parameter from your opening form tag, things should work as expected right up until the point where you overwrite the value with $_POST['name'], which (as stated above) doesn't actually exist. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509861 Share on other sites More sharing options...
cyberRobot Posted April 24, 2015 Share Posted April 24, 2015 (edited) Now, if you omit the 'action' parameter of the form, it'll post to itself by default - the interesting thing here is that it means the URL will still be intact including your $_GET variables. So, if you remove the "action='createworkorder.php'" parameter from your opening form tag, things should work as expected right up until the point where you overwrite the value with $_POST['name'], which (as stated above) doesn't actually exist. Technically, it's being overwritten by $POST['name'] which will never work with the form. Note the missing underscore. Edited April 24, 2015 by cyberRobot 1 Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509863 Share on other sites More sharing options...
maxxd Posted April 24, 2015 Share Posted April 24, 2015 Technically, it's being overwritten by $POST['name'] which will never work with the form. Note the missing underscore. You are correct, sir. Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509865 Share on other sites More sharing options...
ace2go Posted April 24, 2015 Author Share Posted April 24, 2015 Full working code : <?php require 'database.php'; if(!empty($_GET['name'])) { $name = $_GET['name']; } elseif(!empty($_POST['name'])) { $name = $_POST['name']; } else { $name = null; } if ( !empty($_POST)) { // keep track validation $ $dateError = null; $installerError = null; $salesmanError = null; $categoryError = null; $statusError = null; // keep track post values $date = $_POST['date']; $installer = $_POST['installer']; $salesman = $_POST['salesman']; $category = $_POST['category']; $status = $_POST['status']; // validate input $valid = true; if (empty($date)) { $dateError = 'Please enter Date'; $valid = false; } if (empty($installer)) { $installerError = 'Please enter Installer'; $valid = false; } if (empty($salesman)) { $salesmanError = 'Please enter Salesman'; $valid = false; } if (empty($category)) { $categoryError = 'Please enter Category'; $valid = false; } if (empty($status)) { $statusError = 'Please enter Status'; $valid = false; } // insert data if ($valid) { $pdo = Database::connect(); $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $sql = "INSERT INTO workorder (name, date, installer, salesman, category, status) values(?, ?, ?, ?, ?, ?);"; $q = $pdo->prepare($sql); $q->execute(array($name,$date,$installer,$salesman,$category,$status)); Database::disconnect(); header("Location: workorders.php"); } } ?> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <link href="css/bootstrap.min.css" rel="stylesheet"> <script src="js/bootstrap.min.js"></script> </head> <body> <div class="container"> <div class="span10 offset1"> <div class="row"> <h3>Create a Workorder</h3> </div> <form class="form-horizontal" action="createworkorder.php" method="post"> <input type="hidden" name="name" value="<?php echo htmlentities($name); ?>"> <div class="control-group <?php echo !empty($dateError)?'error':'';?>"> <label class="control-label">Date</label> <div class="controls"> <input name="date" type="text" placeholder="Date" value="<?php echo !empty($date)?$date:'';?>"> <?php if (!empty($dateError)): ?> <span class="help-inline"><?php echo $dateError;?></span> <?php endif; ?> </div> </div> <div class="control-group <?php echo !empty($installerError)?'error':'';?>"> <label class="control-label">Installer</label> <div class="controls"> <input name="installer" type="text" placeholder="Installer" value="<?php echo !empty($installer)?$installer:'';?>"> <?php if (!empty($installerError)): ?> <span class="help-inline"><?php echo $installerError;?></span> <?php endif;?> </div> </div> <div class="control-group <?php echo !empty($salesmanError)?'error':'';?>"> <label class="control-label">Salesman</label> <div class="controls"> <input name="salesman" type="text" placeholder="Salesman" value="<?php echo !empty($salesman)?$salesman:'';?>"> <?php if (!empty($salesmanError)): ?> <span class="help-inline"><?php echo $salesmanError;?></span> <?php endif;?> </div> </div> <div class="control-group <?php echo !empty($categoryError)?'error':'';?>"> <label class="control-label">Category</label> <div class="controls"> <input name="category" type="text" placeholder="Category" value="<?php echo !empty($category)?$category:'';?>"> <?php if (!empty($categoryError)): ?> <span class="help-inline"><?php echo $categoryError;?></span> <?php endif; ?> </div> </div> <div class="control-group <?php echo !empty($statusError)?'error':'';?>"> <label class="control-label">Status</label> <div class="controls"> <input name="status" type="text" placeholder="Status" value="<?php echo !empty($status)?$status:'';?>"> <?php if (!empty($statusError)): ?> <span class="help-inline"><?php echo $statusError;?></span> <?php endif; ?> </div> </div> <div class="form-actions"> <button type="submit" class="btn btn-success">Create</button> <a class="btn" href="workorders.php">Back</a> </div> </form> </div> </div> <!-- /container --> </body> </html> Thanks to everyone for their help!!! Quote Link to comment https://forums.phpfreaks.com/topic/295829-cannot-insert-id-into-php-pdo-array/#findComment-1509866 Share on other sites More sharing options...
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