php switch only using the default code block

[morena]

I have a php switch statement and for some reason php switch is only executing the default code in the default block but not in the case block, i check if my variable is isset first, then use switch to select data from my DB, even if i do var_dump($cname); it shows that variable $cname corresponds with my first case, what is the problem here?

 here is the code

$sel = 1;
    $sql = "(select * from insurance_companies WHERE id='$eop' LIMIT $sel)";
    foreach ($pdo->query($sql) as $row){ 
    $cID = $row['id'];  
    $cname = $row['name'];          
    }
 if  (isset($cname)) {
                    switch ($cname) {
                        case 'CASH':
                            $query= "SELECT test FROM cash_procedures WHERE test LIKE '%$did%'";
                 $result= $con->query($query);
 break;

                        default:
                              $query= "SELECT test FROM procedures WHERE test LIKE '%$did%'";
                 $result= $con->query($query);

}
    }

[requinix]

Did var_dump($cname) show exactly

string(4) "CASH"

[morena]

yes it did

[requinix]

Then what you're describing is not possible.

 

1. You didn't mention where you put the var_dump, but assuming it came sometime after the (unnecessary) foreach loop then it shouldn't matter.

2. The crazy indentation suggests you pieced together your post from different pieces of code, rather than from one complete block.

3. You say it executed the default case - how do you know that? Have you put debugging statements (eg, an echo) in each case to see whether it really is executing that way?

[taquitosensei]

you don't have a break after your default case. Not sure if that would cause this though. 

[Jacques1]

No. A break would be entirely redundant.