Proper way to write this conditional

[stoggafu]

I would like this to echo the $val['value'] if it has a value, and to display the number 0 if it does not. I have tried a few different ways of trying to get it to show 0 for the ones that have no value, but cannot seem to get both to work conditionally...Thank you

<?php

foreach($_44 as $val)

    if ($val['feat'] == '7mr') {

        echo $val['value'];

    }

?>

[requinix]

What does "no value" mean? Does not exist in the array at all? Exists but the value is an empty string? Value is null? Something else?

[stoggafu]

What does "no value" mean? Does not exist in the array at all? Exists but the value is an empty string? Value is null? Something else?

 

 

Value does not exist. Thank you.

[Sepodati]

Use isset().

 

echo (isset($val['value'])) ? $val['value'] : 0;

Edited September 16, 2017 by Sepodati

[stoggafu]

I tried this, but it is not giving me any output when the value does not exist, only when it exists..
 

<?php
foreach($_44 as $val) {
    if ($val['feat'] == '7mr'){
        echo isset($val['value']) && !empty($val['value']) ? $val['value'] : '0';
	}
}
?>

[requinix]

Works for me.

[stoggafu]

Works for me.

 

What if is there is no ['feat'] > ['value'] at all for return? Would I need to write a separate if?

[requinix]

Maybe. Can't say for sure what you should do since I have no idea what the $_44 array is or what the "feat" and "value" mean. Maybe it's an error for it to not exist. Maybe the array is empty to begin with. Maybe something else.

[Barand]

The way to write the conditions is to decide what the conditions are first then start to code them, as opposed to the method you are asking us to take - write some conditions then introduce others once that is done.