find absolute smallest value (close to zero)

[nestaho]

// there is a problem in the for loop. I am an ameteur, please help me to correct and give explanation

 

 

 

fscanf(STDIN, "%d",

    $n // the number of temperatures to analyse

);

 

$minTemp = -273;

$maxTemp = 5526;

 

$inputs = fgets(STDIN);

$inputs = explode(" ",$inputs);

 

$near = $inputs[0];

 

 

for ($i = 0; $i < $n; $i++)

{  

 if (abs($near) <= abs($inputs[$i+1]) {

     $near = abs($inputs[$i+1])

     

    }

echo($near);

}

[requinix]

 if (abs($near) 
     $near = abs($inputs[$i+1])


    }

Explain to me, in words, exactly what that is doing.

[nestaho]

I am a bit confused actually

 

I wanna write

if abs($near) is smaller than the absolute of next number

then abs($near) stay the same

otherwise if abs($near) is larger than the absolute of next number

the abs($near) change to next number

[requinix]

if abs($near) is smaller than the absolute of next number

then abs($near) stay the same

In other words, don't do anything.

 

otherwise if abs($near) is larger than the absolute of next number

the abs($near) change to next number

This is the one to focus on. How does this logic compare to what you've written in the code?

[nestaho]

CAN U REWRITE THE CODE FOR ME? PLEASE...

I rewrite code as follow, with following error

 

Parse error: syntax error, unexpected ';' in the answer code at line 20

 

 

--------------------------------------------------------------------------------------------

fscanf(STDIN, "%d",

$n // the number of temperatures to analyse

);

 

$inputs = fgets(STDIN);

$inputs = explode(" ",$inputs);

 

$near = abs($inputs[0]);

 

 

for ($i = 0; $i < $n; $i++)

{ 

if (abs($near) >= abs($inputs[$i+1]) {

    $near = abs($inputs[$i+1]);

 

}

echo($near);

}

[requinix]

CAN U REWRITE THE CODE FOR ME? PLEASE...

No.

 

You solved the problem. That's great. Now you just have to deal with a typo:

if (abs($near) >= abs($inputs[$i+1]) {

Count your parentheses.