JonnyDriller Posted February 27, 2020 Share Posted February 27, 2020 I have a situation were I need to just get a simple location. I don't want any while loops or any of that jazz. I just want 1 string location every time. <?php $ider = $_GET['id']; $conn = mysqli_connect("localhost", "Me", "pass", "MyDB"); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT Location FROM LifeSaver1 WHERE id =$ider"; $result = $conn->query($sql); $obj = mysqli_fetch_object($result); $obj2 = $obj->Location; var_dump($obj); ?> This is what it outputs Quote string(11) "Boston" I just need Boston. Can anyone give me a hint? Quote Link to comment https://forums.phpfreaks.com/topic/310142-parsing-problem-with-a-php-array/ Share on other sites More sharing options...
ginerjm Posted February 27, 2020 Share Posted February 27, 2020 How about "echo $obj2"; ?? 1 Quote Link to comment https://forums.phpfreaks.com/topic/310142-parsing-problem-with-a-php-array/#findComment-1574940 Share on other sites More sharing options...
JonnyDriller Posted February 27, 2020 Author Share Posted February 27, 2020 No way... facepalm... ahh well I think I learned a good bit. Legend @ginerjm thx m8 Quote Link to comment https://forums.phpfreaks.com/topic/310142-parsing-problem-with-a-php-array/#findComment-1574942 Share on other sites More sharing options...
ginerjm Posted February 27, 2020 Share Posted February 27, 2020 HTH! Quote Link to comment https://forums.phpfreaks.com/topic/310142-parsing-problem-with-a-php-array/#findComment-1574958 Share on other sites More sharing options...
Psycho Posted February 28, 2020 Share Posted February 28, 2020 For that matter, why have $obj2 at all! Just use $obj->Location where you want that value. Quote Link to comment https://forums.phpfreaks.com/topic/310142-parsing-problem-with-a-php-array/#findComment-1574985 Share on other sites More sharing options...
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