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The below code produces a dropdown and when a selection is made and submitted produces
a table row with a link to the record but the link doesn't work.  suggestions?

---------------------------------------------------------------------------


<!DOCTYPE><html><head>
<title>lookup menu</title>
</head>
<body><center><b>
<form name="form" method="post" action="">

<?php
// error_reporting(0);
error_reporting(E_ALL ^ E_NOTICE);
include 'homedb-connect.php';

//This creates the drop down box
echo "<select name= 'target'>";
echo '<option value="">'.'--- Select account ---'.'</option>';
$query = mysqli_query($con,"SELECT target FROM lookuptbl");
$query_display = mysqli_query($con,"SELECT * FROM lookuptbl");
while($row=mysqli_fetch_array($query))
{echo "<option value='". $row['target']."'>".$row['target']
.'</option>';}
echo '</select>';
?>
<input type="submit" name="submit" value="Submit"/>
</form><center>

<?php
// error_reporting(0);
error_reporting(E_ALL ^ E_NOTICE);
include 'homedb-connect.php';

if(isset($_POST['target']))
{
$name = $_POST['target'];
$fetch="SELECT target, purpose, user, password, email, visits, date,
 saved FROM lookuptbl WHERE target = '".$name."'";
$result = mysqli_query($con,$fetch);
if(!$result)
{echo "Error:".(mysqli_error($con));}

//display the table
        echo '<table border="1"><tr><td bgcolor="#ccffff" align="center">lookup menu</td></tr>
        <tr><td>
        <table border="1">
        <tr>
        <td> Target </td>
        <td> Purpose </td>
        <td> User </td>
        <td> Password </td>
        <td> Email </td>
        <td> Visits </td>
        <td> Date </td>
        <td> Saved </td>
        </tr>';

        while($data=mysqli_fetch_row($result))                              
          {
$url= "http://localhost/home/crud-link.php?target=". $data[0];
$link= '<a href="'.$url.'">'. $data[0]. '</a>';

echo ("<tr><td> $link </td><td>$data[1]</td><td>$data[2]</td><td>$data[3]</td>
<td>$data[4]</td><td>$data[5]</td><td>$data[6]</td><td>$data[7]</td></tr>");
}     
        echo '</table>
        </td></tr></table>';
  }
?>
</body></html>

 

Link to comment
https://forums.phpfreaks.com/topic/310212-help-wmysqli/
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Why don't you var_dump or print_var the contents of $data to debug this.

An obvious concern is that you do not urlencode() $data[0].  

 

$url= "http://localhost/home/crud-link.php?target=". urlencode($data[0]);

 

We need more information than "but the link doesn't work."  What exactly does that mean? 

Probably not related, but the form is user input, and your mysqli queries should be using mysqli_prepare with a bound parameter.

Link to comment
https://forums.phpfreaks.com/topic/310212-help-wmysqli/#findComment-1575176
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