ciresuark Posted May 19, 2020 Share Posted May 19, 2020 I have a form gathering data from the database. There is one field 'country' which is a combo box. The combo box is populated from the countries table which joins the customers table to provide the country specific to the customer. I'm trying to have the combo box display the country associated with the customer. I think I'm close in my code, but unsure. This is a playground to so I can implement on our other site. <?php require_once('database.php'); $sql2 = "SELECT * From countries "; $countries = $db->query($sql2); if(isset($_GET['customerID'])) { $customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT); $sql = "SELECT * FROM customers WHERE customerID =$customerID "; //$sql2 = "SELECT * From countries //INNER JOIN customers ON countries.countryCode=customers.countryCode //WHERE customers.customerID = $customerID"; $stmt = $db->query($sql); } if(isset($_GET['customerID'])){ $customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT); $countryQuery = " {$sql2} INNER JOIN customers ON countries.countryCode = customers.countryCode WHERE customers.customerID = $customerID"; $countriesQuery = $db->prepare($countryQuery); $countriesQuery->execute(['customerID' => $_GET['customerID']]); $selectedCountry = $countriesQuery->fetch(PDO::FETCH_ASSOC); var_dump($selectedCountry); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <!-- the head section --> <head> <title>My Guitar Shop</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <!-- the body section --> <body> <div id="page"> <div id="header"> <h1>SportsPro Technical Support</h1> <p>Sports management software for the sports enthusiast.</p></h1> </div> <div id="main"> <h1>View/Update Customer</h1> <form action="update.php" method="get" > <?php ?> <div id="content"> <!-- display a table of products --> <h2>Customers</h2> <form name="customerInfo"> <?php foreach ($stmt as $cust) { ?> <div> <label>First Name</label> <input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>"> </div><br> <div> <label>Last Name</label> <input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>"> </div><br> <div> <label>Address</label> <input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>"> </div><br> <div> <label>City</label> <input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>"> </div><br> <div> <label>State</label> <input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>"> </div><br> <form action="update.php" method="get"> <select name="country"> <option value=""></option> <?php foreach ($countries->fetchAll() as $country): ?> <option value="<?php echo $country['customerID']; ?> <?php echo isset($customerID) == $selectedCountry['customerID'] ? ' selected':''?> "><?php echo $country['countryName']; ?></option> <?php endforeach;?> </select> </form> </div> <br> <div> <label>Country Code</label> <input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>"> </div><br> <div> <label>Zip Code</label> <input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>"> </div><br> <div> <label>Email </label> <input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>"> </div><br> <div> <label>Phone Number </label> <input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>"> </div><br> <div> <label>Password </label> <input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>"> </div><br> <div> <?php } ?> </div> </div> <form action="UpdateCustomer.php" method="get"> <input type="submit" name="data" value="Update_Data"></input> </form> <div id="footer"> <p> © <?php echo date("Y"); ?> SportsPro, Inc. </p> </div> </div><!-- end page --> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/ Share on other sites More sharing options...
gw1500se Posted May 19, 2020 Share Posted May 19, 2020 Did you look at the resulting page source to check for any HTML errors? Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578189 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 Yes, there are no errors in the code. The top of the page has the var_dump: array(12) { ["countryCode"]=> string(2) "US" ["countryName"]=> string(13) "United States" ["customerID"]=> string(4) "1045" ["firstName"]=> string(9) "Priscilla" ["lastName"]=> string(5) "Smith" ["address"]=> string(8) "Box 1979" ["city"]=> string(6) "Marion" ["state"]=> string(2) "OH" ["postalCode"]=> string(5) "43305" ["phone"]=> string(14) "(800) 555-1669" ["email"]=> string(18) "psmith@example.com" ["password"]=> string(6) "sesame" } I am tried to use this to determine if my query was pulling the information. The section pulling this is: <form action="update.php" method="get"> <select name="country"> <option value=""></option> <?php foreach ($countries->fetchAll() as $country): ?> <option value="<?php echo $country['customerID']; ?> <?php echo isset($customerID) == $selectedCountry['customerID'] ? ' selected':''?> "><?php echo $country['countryName']; ?></option> <?php endforeach;?> </select> </form> and I think I need to update: <?php echo isset($customerID) == $selectedCountry['customerID'] ? ' selected':''?> It isn't right as the combo box isn't highlighting "United States". Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578190 Share on other sites More sharing options...
gw1500se Posted May 19, 2020 Share Posted May 19, 2020 If you looked for an error you won't find it. I meant look at the generated HTML source and see if the structure and data for the option box is there and correct. If it is not, you should be able to see what was built and what is missing/wrong. Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578191 Share on other sites More sharing options...
Barand Posted May 19, 2020 Share Posted May 19, 2020 Build you country combo options from the country table. The value for each option should be the id/code for the country Here's an example <?php $res = $db->query("SELECT customer_id , fname , lname , country FROM customer LIMIT 10 "); $tdata = ''; foreach ($res as $row) { $tdata .= "<tr> <td>{$row['fname']} {$row['lname']}</td> <td style='text-align: center;'><select name='country'>" . countryOptions($db, $row['country']) . "</select><td> </tr>"; } function countryOptions(PDO $db, $current) { $opts = "<option value=''>- select country -</option>\n"; $res = $db->query("SELECT country_id as id , country_name as name FROM country ORDER BY name "); foreach ($res as $row) { $sel = $row['id'] == $current ? 'selected' : ''; $opts .= "<option $sel value='{$row['id']}'>{$row['name']}</option>\n"; } return $opts; } ?> <!DOCTYPE html> <html lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Example</title> </head> <body> <table style='width: 600px;'> <tr><th>Name</th><th>Country</th></tr> <?=$tdata?> </table> </body> </html> Example data and ouput Table: customer Table: country +-------------+----------+-----------+---------+ +------------+--------------+ | customer_id | fname | lname | country | | country_id | country_name | +-------------+----------+-----------+---------+ +------------+--------------+ | 1 | Wanda | Denning | 1 | | 1 | England | | 2 | Tom | Westbrook | 2 | | 2 | Scotland | | 3 | Georgina | Jones | 3 | | 3 | Wales | | 4 | Hannah | Wentworth | 1 | | 4 | N. Ireland | | 5 | Roy | Egon | 4 | +------------+--------------+ | 6 | Len | Elridge | 1 | | 7 | Sam | Patterson | 2 | | 8 | Charles | Knight | 1 | | 9 | Gerald | Watts | 1 | | 10 | Tom | Bowles | 4 | +-------------+----------+-----------+---------+ 1 Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578193 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 I don't know if it makes it more difficult, but the countries are stored in a different table with the country abbreviation which is why I have the join. In the results you show, are you able to see the other options if a user needed to make updates? Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578195 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 33 minutes ago, gw1500se said: If you looked for an error you won't find it. I meant look at the generated HTML source and see if the structure and data for the option box is there and correct. If it is not, you should be able to see what was built and what is missing/wrong. I did what you mentioned and I am receiving an Undefined index: customer ID on line 94. Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578196 Share on other sites More sharing options...
Barand Posted May 19, 2020 Share Posted May 19, 2020 Of course - all the options are in the combo but the relevant one is displayed. Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578197 Share on other sites More sharing options...
Barand Posted May 19, 2020 Share Posted May 19, 2020 Is line 94 this one.. <option value="<?php echo $country['customerID']; ?> where you are trying to use "customer_id" as the value for your country, instead of the country_id/code? Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578199 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 1 minute ago, Barand said: Is line 94 this one.. <option value="<?php echo $country['customerID']; ?> where you are trying to use "customer_id" as the value for your country, instead of the country_id/code? I'm not sure why I did it that way. I changed it to countryName. The countries table only has countryCode and CountryName. There are no ids. After I changed it to <option value="<?php echo $country['countryName']; ?> the error went away. This is what the inspected element looks like. <option value="Sao Tome and Princip selected ">Sao Tome and Princip</option> If I am seeing this right, I need to move the " to have the selected outside the quote. Right now all options are showing as selected. Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578200 Share on other sites More sharing options...
Barand Posted May 19, 2020 Share Posted May 19, 2020 The value should be the country code (which is what is in your customer table) Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578201 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 Agreed. Right now as I look at this I think the primary issue is I am not reading the input from the "customer". The start of the foreach loop looks at countries which is: SELECT * From countries (sql2), which lists all the countries available within the db and makes them available within the combobox. <?php foreach ($countries->fetchAll() as $country): ?> <option value="<?php echo $country['countryName']; ?> <?php echo isset($selectedCountry) == $selectedCountry['countryName'] ? ' selected':''?> "><?php echo $country['countryName']; ?></option> <?php endforeach; ?> As I am looking through this I think the code line below is my issue. As I'm looking at the selected country twice and not gathering what the country should be to verify it is correct. Does that sound right? <?php echo isset($selectedCountry) == $selectedCountry['countryName'] ? ' selected':''?> In non-php I want to check the selected country from the db against the customerID's country and highlight it. $countryQuery = " {$sql2} INNER JOIN customers ON countries.countryCode = customers.countryCode WHERE customers.customerID = $customerID"; $countriesQuery = $db->prepare($countryQuery); $countriesQuery->execute(['customerID' => $_GET['customerID']]); $selectedCountry = $countriesQuery->fetch(PDO::FETCH_ASSOC); Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578202 Share on other sites More sharing options...
ciresuark Posted May 19, 2020 Author Share Posted May 19, 2020 After some playing and talking it out loud to myself I was able to figure it out. The code block should be like below.I had a double quote in the wrong spot, and the statement off a little bit. foreach ($countries->fetchAll() as $country): ?> <option value="<?php echo $country['countryName']; ?>" <?php echo isset($selectedCountry) && $selectedCountry['countryName'] == $country['countryName'] ? ' selected':''?> ><?php echo $country['countryName']; ?></option> <?php endforeach; Thank you for the help. Quote Link to comment https://forums.phpfreaks.com/topic/310816-combobox-show-information-selected-from-database/#findComment-1578203 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.