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Hey Guys,

 

I'm really struggling to find whats wrong with this code. The form before submit has several checkboxes as part of an array which is below

     
<?php
$conn = new mysqli($servername, $username, $password, $dbname);    
$sql = "SELECT * FROM `engineers`";
$result = $conn->query($sql);
        
while($row = mysqli_fetch_assoc($result)) {
    
    $endid = $row["endid"];
    $resource_name = $row["resource_name"];
    $resource_email = $row["resource_email"];
    $picture = $row["picture"];
    
    echo "<label>".$resource_name."</label><input type='checkbox'  class='form-control' name='engineers[]' value=''.$endid.''><br>";
    
         }
    
        ?>

The next page then goes to this and I get the error "Fatal error: Uncaught Error: Call to undefined function mysql_connect() in /homepages/39/d837976904/htdocs/Scheduler/add_job3.php:10 Stack trace: #0 {main} thrown in /homepages/39/d837976904/htdocs/Scheduler/add_job3.php on line 10"

<?php
// Initialize the session
session_start();

$process = $_GET["process"];

include "Includes/config.php";
include "Includes/db.php";


mysql_connect($servername, $username, $password) or die(mysql_error());
mysql_select_db($dbname) or die(mysql_error());

$checkBox = implode(',', $_POST['engineers']);

if(isset($_POST['submit']))
{       
    $query1="INSERT INTO job_activity (endid) VALUES ('" . $checkBox . "')";     

    mysql_query($query1) or die (mysql_error() );

    echo "Complete";

}

?>
 

Can anyone help with the code please :(

Link to comment
https://forums.phpfreaks.com/topic/311381-help-with-adding-checkbox-into-mysql/
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  • 2 weeks later...

This seems to be because you're mixing obsolete sql with sqli. You can't use both in the same database call. The big problem I see with this is that you should be using prepared statements in the first place.

Edited by bakertaylor28
This thread is more than a year old. Please don't revive it unless you have something important to add.

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