Convert string into already available variable ?

[Minzer]

//$value1 = $_POST['game'];

$value1 = "game7h";

if (strpos($value1, 'a')) {
$team = 'a';
}elseif (strpos($value1, 'h')) {
$team = 'h';
}      
if (strpos($value1, '7')) {
$num = '7';
} elseif (strpos($value1, '8')) {
$num = '8';
} elseif (strpos($value1, '9')) {
$num = '9';
}

$gm7hodds = $games[41]["BP"];
$gm7aodds = $games[40]["BP"];

$gm8hodds = $games[47]["BP"];
$gm8aodds = $games[46]["BP"];

$gm9hodds = $games[53]["BP"];
$gm9aodds = $games[52]["BP"];


/* 
$getratio = $num + $team;

echo $getratio;

Team is not a math operation so I'll finesse that later.

*/


$findratio = 'gm' . $num . 'h' . 'odds';
echo $findratio;

gm7hodds

How would I add the $ to it and return its array value $gm7hodds?

Solved whoops ->

echo eval('return $'. $findratio. ';');

Edited April 28, 2021 by Minzer
solved

[requinix]

No. Using eval is a really bad idea. There are always better solutions to problems than using eval.

$num is the only unknown part, right? Look at this:

$gm = array(
	9 => array(
		"hodds" => $games[53]["BP"],
		"aodds" => $games[52]["BP"]
	)
);

echo $gm[$num]["hodds"];

Really easy.