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Hi guys

I'm super new to PHP, so bear with me!  But I have a super simple code here that will display all images in a folder, and print the 'header' IPTC metadata and then print the filename.  My query is this -- it currently repeats the last available IPTC header, even if the next image doesn't have any metadata stored in it.  So how can I tell the code to simply not print anything at all if the IPTC data isn't stored in the file?

Thanks a lot

James  (here's the code)

 

<?php
$files = glob("*.*");

    for ($i=0; $i<count($files); $i++) {
        $image = $files[$i];

        echo '<img src="'.$image .'" title="'.$image .'" alt="'.$image .'" width="5%"/>'."<br />";

            $picinfo = array();
            getimagesize($image, $picinfo);

            if(isset($picinfo['APP13']))
            {
            $iptc = iptcparse($picinfo["APP13"]);
            }

            if (is_array($iptc)) {
            $description = $iptc['2#105'][0]; /* IPTC 'Header' metadata */
            }

            print_r($description);
            print "<br />"; print $image ."<br /><br />"; /* Print filename */
    }
?>

You already have something that will print information if it's available. What's more, it makes sense: if you have $iptc data then print what's in it. Logical. Obviously, that then means that if you don't have $iptc data then it won't print. Also logical.

So then, if you don't want it to print anything, you need to make sure that "you don't have $iptc data" is true. Thoughts on how you can make that happen?

12 hours ago, requinix said:

You already have something that will print information if it's available. What's more, it makes sense: if you have $iptc data then print what's in it. Logical. Obviously, that then means that if you don't have $iptc data then it won't print. Also logical.

So then, if you don't want it to print anything, you need to make sure that "you don't have $iptc data" is true. Thoughts on how you can make that happen?

Ahh I figured it out with an 'if else' statement :) Just wasn't sure how to phrase it correctly, but it's working now.

 

 

<?php
$files = glob("*.*");

    for ($i=0; $i<count($files); $i++) {
        $image = $files[$i];

        echo '<img src="'.$image .'" title="'.$image .'" alt="'.$image .'" width="5%"/>'."<br />";

            $picinfo = array();
            getimagesize($image, $picinfo);

            if(isset($picinfo['APP13']))
            {
            $iptc = iptcparse($picinfo["APP13"]);
            }

            if (empty($picinfo["APP13"])) {
            $description = "";
            } else {
            $description = $iptc['2#105'][0]; /* IPTC 'Header' metadata */
            print_r($description);
            print "<br />";
            }
            
            print $image ."<br /><br />"; /* Print filename */
    }
?>

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