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I am trying to put a column from a database table into a select input .How can I catch the value that I chose using php?

Here is my code.Thanks in advance

<?php
	$stmt = $con->query("SELECT size FROM size INNER JOIN
			 inventory ON size.idSize = inventory.idsize 
			WHERE id_item =$idd");
while($row = $stmt->fetch_assoc()) {
	
?>
<form action='' method="post">
<select name='size' id="size" class='size'>
<option  value="<?php $row ?>"><?php echo  $row['size'] ?></option>
 </form>
<?php
}
?>

 

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https://forums.phpfreaks.com/topic/314658-select-options-value/
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Use prepared statements instead of putting user-provided variables directly in to the query

<?php
    $stmt = $con->prepare("SELECT DISTINCT size 
                           FROM size 
                                INNER JOIN
                                inventory ON size.idSize = inventory.idsize
                           WHERE id_item = ?
                           ORDER BY size
                           ");
    $stmt->bind_param('i', $idd);
    $stmt->execute();
    $stmt->bind_result($size);
    $opts = "";
    while($row = $stmt->fetch() {
        $opts .= "<option value='$size'>$size</option>\n";
    }
?>

<form action='' method="post">
    <select name='size' id="size" class='size'>
        <?=$opts?>
    </select>
</form>

 

You are trying to create a drop-down list of the items found with your query, correct?   Do you want the user to be able to pick just one item or several?  If you want to allow multiple picks at once you need to add that option to your select tag and then use an array name for the name attribute of the tag.  Then your php can process that array instead of just one item.

Look up the tag in an html reference to learn about the multiple select.  Then change the name on your select tag to 'size[]' to make it an array.  Then in the code that will handle the POST input you will use a loop on the 'size' array to collect all of the items picked.

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