Warning tells me that Count () needs to be an array

[nextgen]

Friends i have a had a few rough years and when i get back home i started to tinker with my old website. I have cleared a ton of deprecation errors etc but the last 2 have me stumped as i am not a coder i was an electrician. Here is my code.

$nfield = $_POST[nfield];
    if (count($nfield) > 0)
    {
        foreach ($nfield as $key => $var)
        {
            $var = check_html($var, "nohtml");
            $var = trim(htmlspecialchars($var, ENT_QUOTES));
            $nfield[$key] = $var;
        }
    }

Please, if anyone can help i would appreciate it.  

[Barand]

Then $_POST['nfield'] is not an array as exepected. You need to check why.

What is the form markup code where it originates?

[dodgeitorelse3]

The $_POST[nfield] should be 

$_POST['nfield']

Edited August 9, 2022 by dodgeitorelse3
Typo

[nextgen]

usercp_register.txt

 

The issue is from line 94 of the above text which is stopping users from registering on my site

[kicken]

The usual cause in a scenario like this is that your $_POST['nfield'] input simply doesn't exist and as such $nfield would be null and not an array.   You could use the null-coalescing operator to handle that.

$nfield = $_POST['nfield'] ?? [];

If that were the case and you have your error reporting turned up fully, you should also be getting errors regarding 'Undefined index: nfield' (and in your case, warnings about an undefined constant since you don't have quotes around the key name).

Do a simple var_dump($_POST['nfield']) prior to that line and you can see what the field is and use that to determine how it should be fixed.