phppup Posted November 9, 2022 Share Posted November 9, 2022 I'm not sure if I've got a syntax or an implementation problem, but I've created a form entirely in PHP. Essentially, each item is pulled from an array and named with the associated key index. Each item is attached to a drop-down menu containing integers 0 thru 10 (indicating the quantity for an order). On submission of the form, I want the selected values to be retained. If other fields of the form are not complete, error messages will display, and I want these values to be retained rather than resetting. for($i = 0; $i < 11; $i++){ $quantity .= "<option>".$i."</option>"; } for($i = 0; $i < count($arr); $i++){ echo "select name='amt_".$i."'>".$quantity."</select>"; } How can I have each drop-down retain it's value after a (failed) submit effort? Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/ Share on other sites More sharing options...
ginerjm Posted November 9, 2022 Share Posted November 9, 2022 Option tags are not input tags. The value you give them when you write out the html will always be there. As for what you are asking, I have no clue what you want to do. Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602350 Share on other sites More sharing options...
Solution Barand Posted November 9, 2022 Solution Share Posted November 9, 2022 Set the "selected" attributes of the options containing the selected values in each dropdown For example <?php if ($_SERVER['REQUEST_METHOD']=='POST') { echo "You ordered the following quantities<br>"; foreach ($_POST['qty'] as $i => $qty) { if ($qty) { echo "Item $i : $qty<br>"; } } echo "<hr>"; } function qtyOptions($current) { $opts = ''; for ($i=0; $i<11; $i++) { $sel = $i==$current ? 'selected' : ''; $opts .= "<option $sel value='$i'>$i</option>\n"; } return $opts; } ?> <!DOCTYPE html> <html lang='en'> <head> <title>Example</title> <meta charset='utf8'> </head> <body> <form method='POST'> Item 1 <select name='qty[1]'><?= qtyOptions($_POST['qty'][1] ?? 0)?></select> <br> Item 2 <select name='qty[2]'><?= qtyOptions($_POST['qty'][2] ?? 0)?></select> <br> Item 3 <select name='qty[3]'><?= qtyOptions($_POST['qty'][3] ?? 0)?></select> <br> <br> <input type='submit'> </form> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602352 Share on other sites More sharing options...
Psycho Posted November 9, 2022 Share Posted November 9, 2022 Let me add to Barand's response. The typical process I take with forms is as follows: Form pages will POST to themselves When a form page loads it will first determine if a submission was made. If no submission is made, proceed to creating the form If a submission was made, then I will have the code go through form validation logic to ensure that all required data was submitted and that all submitted data is appropriate (e.g. a numeric field should have a numeric value, a date field should include a value that can be interpreted as a date, if something should match a DB id value, make sure that value exists, etc.) During the validation, for any errors that are encountered save appropriate error messages in an array/object, then proceed to creating the form. If no errors in validation, then execute the code to act on the submitted data - e.g. do a DB INSERT. Then redirect to a confirmation page. CREATE THE FORM: If there was no form submission or if there were errors in the data validation, create the form for user input. If there were errors, you can repopulate any valid data back into the appropriate fields so the user does not need to reenter. For errors, you can list them all at the top of the page (easy) or you can list them out above/below the individual fields where the errors occurred. You would just need to store the errors in the array/object in a way to correspond them to the input fields where they originated. I also like to create functions for building my various input fields. That way I can call the function with appropriate parameters so it can build the field either with the default/empty value or with a previously entered value. That way I don't have to write the same 6-10 lines of code to handle those two scenarios for every input field. Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602357 Share on other sites More sharing options...
phppup Posted November 10, 2022 Author Share Posted November 10, 2022 Quote That way I don't have to write the same 6-10 lines of code to handle those two scenarios for every input field. @Psycho Thanks for the outline of information. I've begun to understand and get comfortable with the effectiveness of arrays (I think... LOL). This is an attempt at using arrays meaningfully. Thanks for the guidance. @Barand I think I follow what you are doing here, and I'm trying to confirm it to my code. However, my understanding of PHP-shorthand is not very good. Can you elaborate/simplify what this Quote <?= qtyOptions($_POST['qty'][1] ?? 0)?> actually means, please. I realize that: qtyOptions is calling the function and $_POST['qty'][1] will provide a value as $current What is <?= doing? What do the ?? mean? Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602376 Share on other sites More sharing options...
Barand Posted November 10, 2022 Share Posted November 10, 2022 <?= $x ?> is a shorthand version of <?php echo $x ?> $x ?? 0 uses the null coalesce operator (??) and is an alternative to ( isset($x) ) ? $x : 0; In other words, if $x exists, use it, otherwise default to "0"; Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602379 Share on other sites More sharing options...
phppup Posted November 10, 2022 Author Share Posted November 10, 2022 @Barand So I guess at this point my question is, what is the correct syntax to use within the option tag while creating it with PHP? It seems simple enough under "normal conditions", but I am echoing echo "select name='amt_".$i."'>".$quantity."</select>"; the drop-down and using PHP to populate the options through a loop. I can't put an echo inside an echo, can I? I understand that some re-working will be necessary, but my goal was to create the for as a large PHP echo without direct HTML usage. Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602380 Share on other sites More sharing options...
Barand Posted November 10, 2022 Share Posted November 10, 2022 See my example. Use name='amt[$i]' and not name='amt_".$i."' Quote Link to comment https://forums.phpfreaks.com/topic/315506-saving-select-value-on-form/#findComment-1602382 Share on other sites More sharing options...
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