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Dear Team,

 

I had created page for displaying the profile details along with user image.

For that i am using the bellow code to upload and display it. I don't want to use another button for insert the image on database. single button should work both the operations (select and update).

<div class="col-md-4">
                            <div class="profile-img">
                                <img src="../UserImage/<?=$UserImage?>" alt="" />
                                <div class="file btn btn-lg btn-primary">
                                    Change Photo
                                    <input type="file" name="file" />
                                </div>
                            </div>
                        </div>

In 

<?php
    if(isset($_POST['file'])){

		  	$name = $_FILES['file']['name'];
              $target_dir = "UserImage/";
		  $target_file = $target_dir . basename($_FILES["file"]["name"]);
		  // Select file type
  $imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));

  // Valid file extensions
  $extensions_arr = array("jpg","jpeg","png","gif");
		  // Check extension
  if( in_array($imageFileType,$extensions_arr) ){
     // Upload file
     if(move_uploaded_file($_FILES['file']['tmp_name'],$target_dir.$name)){
		 $address = $_POST['address'];
		 $query = "UPDATE users SET User_Image = '$name' WHERE id = '$id'";
		 $result = mysqli_query($conn,$query);

      }
  }
}
    ?>

Can any one help me for this.

Link to comment
https://forums.phpfreaks.com/topic/315657-photo-upload-with-single-button/
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You only need one button to do a file upload.  That a bit of php to get the file and save it somewhere on your server/host.  You will not be saving it in a database though.  Not recommended.  Designate a folder for where to place these files and then save the filename in the database, using a static path in your code to reference it when needed.  When things change you only have to do a bit of file reorganizing to move all of them to wherever you need to put them and then change the static path in your code to point there instead of having to update all the database records with a new path.

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