[SOLVED] can you not have variable in the filename?

[ted_chou12]

$number = $data[$news][3];
echo $number;
will give you 2
and then I wish to plug the two in:
echo file_get_contents("newscomments/comments[[color=red]2[/color]].txt");
so I do this:
echo file_get_contents("newscomments/comments[$number]txt");
but it doesnt work, the two doesnt show up for some reason..
can anyone help me, thanks
Ted.

[Jessica]

The 2 doesn't show, or the file opening fails?
You're missing a . in the second line.

[ted_chou12]

the 2 doesnt show, so instead of "newscomments/comments[2].txt" it opens "newscomments/comments[].txt"...

[ted_chou12]

what do you mean by a . , how do I add it in?

[Jessica]

Look at what you wrote. The first one says .txt, the second says txt.

Since you error does not reflect this typo, that means you didn't actually copy and paste your real code. Your mistake is probably there.
Link?

[ted_chou12]

I found out why, sorry... I accidentally have a space after the number... ;D
Ted

[Jessica]

This is why you should actually post YOUR code, instead of retyping it.

[ted_chou12]

;D
Ted