Upolad File PHP

[Bel]

I did this code in HTML

<label id="read" class="read" for="files">Choose:</label>
           <input type="file" accept="image/*|video/*" name="file" id="file" class="jump" multiple="true">
           <input type="button" id="btlo" class="btload" name="load" value="Load" onclick="Load();">

 

and call function Load() below

 

function Load(){
     var fileInput = document.getElementById("file");  
      var str = new FormData();
       for (i = 0; i < fileInput.files.length; i++) {
         str.append(fileInput.files.name, fileInput.files);
    }   
          
      
      $.ajax({
               url: "upload.php",
               method: "POST",
               data: str,               
               contentType: false,
               cache: false,
               processData: false,  
               beforeSend:function(){
                   $('#respimg').html("Sending...");
               },
               success:function(data){
                       $('#msgret').html(data);                       
                  }
    });
}
 

PHP

<?php
$num = 2;
if (isset($_FILES['file'])){
 for ($i = 0; $i < $num; $i++) {
    
    $nfile = $_FILES["file"]["name"][$i];
    $tfile = $_FILES["file"]["size"][$i];
    $ntemp = $_FILES["file"]["tmp_name"][$i];

}

 

It isn´t work with o if isset but without it´s giving this mensage Notice: Undefined index: file

[kicken]

This:

str.append(fileInput.files.name, fileInput.files);

Should be this:

str.append(fileInput.name, fileInput.files[i]);

You want the name of the form field to used, and the value needs to be a single file not the whole collection.

 

Lastly, your input needs to have the name:

name="file[]"

So that PHP will accept it as an array.

 

[Andou]

Also, while it doesn't affect readability (as far as I can read it, anyway), in the future you should probably use the Code button in the editor to show the code. It makes it easier to scroll down and see what's going on.