shadd Posted July 13 Share Posted July 13 i have a stored procedure as : Create Procedure Update_studentinfo ( IN p_id INT, IN p_address varchar(20)) BEGIN UPDATE student_info SET address = p_address WHERE id = p_id; select "successful as result;" END // And works fine on the server mysql. how can I get the confirmation in Php $mSuccessMessage = Update_studentinfo(125, 'Shimla'); Quote Link to comment https://forums.phpfreaks.com/topic/322315-getting-the-feedback-in-php/ Share on other sites More sharing options...
gw1500se Posted July 13 Share Posted July 13 $mSuccessMessage=mysql_query("Update_studentinfo(125, 'Shimla')"); Quote Link to comment https://forums.phpfreaks.com/topic/322315-getting-the-feedback-in-php/#findComment-1629899 Share on other sites More sharing options...
Barand Posted July 13 Share Posted July 13 TABLE: student_info +-----+---------+ | id | address | +-----+---------+ | 125 | xyz | | 126 | bbb | +-----+---------+ Procedure DELIMITER $$ CREATE PROCEDURE `Update_studentinfo`( IN p_id INT, IN p_address varchar(20)) BEGIN UPDATE student_info SET address = p_address WHERE id = p_id; select "successful as result"; END$$ DELIMITER ; ; PHP $res = $pdo->query("CALL update_studentinfo(125, 'Shimla')"); echo $res->fetchColumn(); Output successful as result TABLE student_info +-----+---------+ | id | address | +-----+---------+ | 125 | Shimla | | 126 | bbb | +-----+---------+ Quote Link to comment https://forums.phpfreaks.com/topic/322315-getting-the-feedback-in-php/#findComment-1629904 Share on other sites More sharing options...
shadd Posted July 15 Author Share Posted July 15 On 7/14/2024 at 2:46 AM, Barand said: TABLE: student_info +-----+---------+ | id | address | +-----+---------+ | 125 | xyz | | 126 | bbb | +-----+---------+ Procedure DELIMITER $$ CREATE PROCEDURE `Update_studentinfo`( IN p_id INT, IN p_address varchar(20)) BEGIN UPDATE student_info SET address = p_address WHERE id = p_id; select "successful as result"; END$$ DELIMITER ; ; PHP $res = $pdo->query("CALL update_studentinfo(125, 'Shimla')"); echo $res->fetchColumn(); Output successful as result TABLE student_info +-----+---------+ | id | address | +-----+---------+ | 125 | Shimla | | 126 | bbb | +-----+---------+ what if i used prepared statement inside procedure will it affect the output in php set @Updateanswer_sql=CONCAT('UPDATE student_info SET address =', p_address,' WHERE id =', p_id); PREPARE sUpdateanswer FROM @Updateanswer_sql; EXECUTE sUpdateanswer; DEALLOCATE PREPARE sUpdateanswer; select "successful as result"; Quote Link to comment https://forums.phpfreaks.com/topic/322315-getting-the-feedback-in-php/#findComment-1630139 Share on other sites More sharing options...
Solution Barand Posted July 15 Solution Share Posted July 15 The purpose of a prepared statement is to avoid placing variable contents directly into the query (and thus avoid SQL injection attacks) by using placeholders and parameters. Using a stored procedure does the same thing. Therefore using a prepared statement inside a stored procedure is a "belt and braces" approach and unnecessary overkill. You should note that your use of prepare is incorrect as you are not using placeholders, but placing the values into the query via concatenation, and is therefore a waste of time anyway. Quote Link to comment https://forums.phpfreaks.com/topic/322315-getting-the-feedback-in-php/#findComment-1630157 Share on other sites More sharing options...
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