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Error in if clause


feri_soft

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Do you see error here. I have e strict and e all but i dont see a mistake:

[code]$sstep = $_GET['step'];
$reffer = $_SERVER['HTTP_REFERER'];
if (!isset($_GET['step']) || $sstep != 2 || $reffer != 'http://' . $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'] . '?step=1') {
exit;
}[/code]

However when i remove it everything is fine else it doesnt work
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https://forums.phpfreaks.com/topic/33218-error-in-if-clause/
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Yes but i have tested directly with HTTP_REFERER  array, but nothing.

PS
[quote]i could never get the HTTP_REFERER to work[/quote]

With me its working. When i seperate the two clauses between the != they are showing the same thing...??! Why then no comparing. I just get a blanc page because of the exit()
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https://forums.phpfreaks.com/topic/33218-error-in-if-clause/#findComment-157419
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