strtoupper() inside a preg_replace()

[The Little Guy]

I would like to take this and uppercase the $0
[b]$nedit = "Don't 'n sfsdf";
preg_replace('/(\s\'\w)/', '$0', $nedit);[/b]


if I do this:
[b]preg_replace('/(\s\'\w)/', strtoupper('$0'), $nedit);[/b]

nothing happens  I know it is matching, because we take $0 and make it some random thing, and it finds it.

[corbin]

So what exactly is $0 supposed to be?

[Hypnos]

If that's a var, remove the quotes.

[corbin]

It does work by the way.  Preg_replace doesn't automatically alter variables (you may realize that, but in your post you don't use it that way), so it's necessary to echo it or $var = preg_replace with it.

[The Little Guy]

It doesn't work


Here is the actual function:
[code]
<?php
function edit_name($nedit){
#$nedit = strtolower($nedit);
$nedit = str_replace(array("/", "&", "  "), array("", "and", " "), $nedit);
$nedit = preg_replace('/^(a|an|the)\s+(.+)/i', '$2, $1', $nedit);
# $nedit = preg_replace('/(?<![a-z]\')\b[a-z]/e', "strtoupper('$0')", $nedit);
#$nedit = preg_replace('/^([^\']*)\B(\'\w)(.*)$/', "$0" . strtoupper('$1') . "$2", $nedit);
$nedit = preg_replace('/(\s\'\w)/', '$0', $nedit);
return $nedit;
//return /*addslashes(*/$nedit /*)*/;
}


echo edit_name("Don't 'n sfsdf");
echo $repls;

?>
[/code]

And here are the results: http://viplyrics.com/testing.php

[The Little Guy]

the problem is that it doesn't know that $0 is supposed to match something from the first part, I don't know how to do the matching like in an .htaccess file.  Anyone Help?

[TripleDES]

Bumping this thread.  I have a similar scenario.  See this string:

 

$subject = "i am [[happy]] today";

 

I'd like to only change happy to uppercase.

 

 

$pattern = "/\[\[.+?\]\]*/";

preg_replace($pattern, strtoupper(??whatdoidohere??), $val);

[RussellReal]

try \0 instead of $0 but I'm going to do a few tests right now and get back to you wait like 2 mins unless sum1 smarter than me gets to it first lol

[RussellReal]

<?php
$a = "hello how ArE you?";
echo preg_replace("/\b(are)\b/ie","strtoupper('\\1')",$a);
?>

 

you need the /e modifyer I guess it stands for "eval" lol

[TripleDES]

Still doesn't work:

 

$myarray = "i am [[happy]] today";
$pattern = "/\[\[.+?\]\]*/ie";

foreach ($myarray as $val) {
$val = preg_replace($pattern, "strtoupper('\\1')", $val);
print $val . "\n";
}

[TripleDES]

Ahh...I needed this: '\\0'

 

Can you explain the significance of \\0, \\1, etc..??

[RussellReal]

they are basck references

 

\0 will be the whole string captured inside of the pattern..

 

\1 would be the first capturing group

\2 wouldbe the second

\3 would be the third.. etc

 

capturing groups are ( )

 

and non-capturing groups are (?: )

[DarkWater]

<?php
$nedit = preg_replace('/(\s\'\w)/e', 'strtoupper("$1");', $nedit);

 

Have fun.