Adding numbers in an array

[coolman1985]

Hello and thank you for taking the time to read my thread.

I am trying to add  numbers I have loaded into an array. I have no problem adding sequential numbers, however when a number is missing I cant do it. Here is an example

Sequential: 1,2,3,4,5,6
The code I wrote

Lets say $files is an array containing numbers 1 through 6 and is in descending order “rsort”.

for($j = 1; $j <= $files[0]; $j++){
$value_high = $num_high + $j;
$num_high = $value_high;
}
$count_high = $GLOBALS['value_high'];
echo $count_high;
this script would output 21

Now what if i wanted to add 1,2,3,5,6.. i skipped 4
answer should be 17, but i dont know how to do that?

thanks agian.

[Jessica]

if the array just doesn't have a 4, instead of for, use foreach()

If it has 4 and you want to skip it, just do
if($i != 4){
}

[coolman1985]

well, it's not allways 4 thats missing it could be 1,3,4 missing 2, or so on. there howerver will never be more than one missing number.

[Jessica]

So use foreach

[coolman1985]

I could use foreach() and have the script auto detect which number in the sequence I am missing. I need this because my script actually reads files form a directory for example 1.txt, 2.txt, and 3.txt and so on. If a file is deleted I want to be able to know which one. Could I still write something with foreach() to do this?

[coolman1985]

I got it, thank you :D