Displaying either Default image vs Image that exists?!?!

[suess0r]

hey,

i'm trying to display images that exist in my web folder /images and if not then to use my default image. Here's the code i'm using, but unfortunetely i keep getting the default image no matter what. Is there another way to see if the image exists other than the way i'm doing it... do i need to search the full directory before the /images/clubs/logos/ folder??

[quote]  $defaultImage = "/images/clubs/logos/default.jpg";

            $myImage = "/images/clubs/logos/".$id.".jpg";
           
            if (file_exists($myImage)) {
              $img = $myImage;
            } else {
              $img = $defaultImage;
            }
       
      echo '<p align="center"><img src="'.$img.'" align="center" width="300" height="128"></p>';[/quote]

[ShogunWarrior]

You can use [b]file_exists[/b].

[suess0r]

I did use [b]file_exists[/b], did u not look at the code i posted? but i still keep getting a default image, so there's a problem with my path to $myImage because it's not recognizing if/when they do exist. Anyone give a little help? Do i need to check a full ServerPath or something, or entire URL before it? Anyone give a little help please.

[Jessica]

You need to use the full path likely. What is the relation of the /images folder to the folder this file is in?

[suess0r]

the file is in the directory directly above the images folder. this is the full path...

http://www.clb411.com/images/default.jpg
http://www.clb411.com/pg2.php -> calls the image

i did put that full path in the code above for the default and file_exists image and i'm still getting my default image every time. i did an echo just on the file_exists part and it still doesn't find the images that exist. Is there another full path i need to add?

[Jessica]

Can you post the new code?
Where is $id coming from? It's possible it's not set.
Do print $id; to make sure it's what you expect.

[ShogunWarrior]

The problem may be that when your start with a slash [b]/[/b] I think the server looks from the server root, not the document root. So you can use [code] $myImage = $_SERVER['DOCUMENT_ROOT'] . "images/clubs/logos/".$id.".jpg";[/code] I think should work.

[suess0r]

the $id is the clubID and I have named all the images in the logo folder the (clubid.jpg). Here's the loop i'm running through and the $id obviously changes with each club, so i would assume that the $myImage would change as well, but Shogun even after I used the $_SERVER[] path you gave me i'm still getting default images.. maybe i'm missing something.. here's my loop

--above SQL Query commands left out--

[quote]for ($i = 0; $i < mysql_num_rows($result_set); $i++)
{
$landmark = mysql_result($result_set, $i, "Club_Landmark");
$city = mysql_result($result_set, $i, "Club_City");
$name = mysql_result($result_set, $i, "Club Name");
$address = mysql_result($result_set, $i, "Club Address");
$phone = mysql_result($result_set, $i, "Club Phone Number");
$state = mysql_result($result_set, $i, "Club State");
$id = mysql_result($result_set, $i, "ClubID");

if ($i % 2)
{
$bg_color="#D7F57E";
}
else
{
$bg_color="#E1F5A4";
}

echo '
<tr>';


$defaultImage = "http://www.clb411.com/images/clubs/logos/default.jpg";

$myImage = $_SERVER['DOCUMENT_ROOT'] . "images/clubs/logos/".$id.".jpg";



if (file_exists($myImage)) {
  $img = $myImage;
} else {
  $img = $defaultImage;
}
       
 
echo '<td width="25%" wrap bgcolor="'.$bg_color.'">
<b><p align="center"><a href="pg3.php?id='.$id.'"><img src="'.$img.'" align="center" width="190" height="93"></a></p>
</td>
<td width="75%" nowrap bgcolor="'.$bg_color.'">
<font face="arial" size="2">';
echo '<b>Name:</b> <a href="orl3.php?id='.$id.'">'.$name.'</a>';
echo '
<br>
<b>Address: </b>'.$address.'
<br>
<b>Phone: </b><a href="tel:'.$phone.'">'.$phone.'</a>
<br>
</font>
</td>
</tr>
<tr>
<td width="70%" nowrap bgcolor="'.$bg_color.'">

<td>';


}
} else {
echo 'Sorry, no results were found...';
}[/quote]

[Jessica]

But what happens when you print out $myImage?
Just ignore the loop for a moment and do
<img src="'.$myImage.'" />
Does it even show up? Does the image actually exist? What is the value of myImage at this point?

[suess0r]

thanks for your patience jesi, no i did an echo on <img src="'.$myImage.'" /> and the images can't be displayed so they aren't showing they exist. They do indeed exist because the way i have it now i do my call like this...

<a href="pg3.php?id='.$id.'"><img src="/images/clubs/logos/'.$id.'.jpg" align="center" width="60" height="45"></a>

and it prints out the logos fine, but the ones that don't exist i have an ugly no image [x]... so they do exist.

[suess0r]

any ideas?