call a function from php class

[chriscloyd]

Okay i have some functions in my php class but im tyring to call a function from inside my class like below but it does not work heres my code

[code]<?php
class getproject
{
private $id;
    function __construct() {
if (!isset($_GET['project'])) {
$get_project = mysql_query("SELECT * FROM projects ORDER BY id DESC");
$pid = mysql_fetch_assoc($get_project);
$this->id = $pid['id'];
} else {
$this->id = $_GET['project'];
}
    }
function name() {
if ($result = mysql_query("SELECT `title` FROM projects WHERE id = '{$this->id}'")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['title'];
}
}
}
function type() {
if ($result = mysql_query("SELECT `type` FROM projects WHERE id = '{$this->id}'")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['type'];
}
}
}
function start() {
if ($result = mysql_query("SELECT `startdate` FROM projects WHERE id = '{$this->id}'")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['startdate'];
}
}
}
function enddate() {
if ($result = mysql_query("SELECT `enddate` FROM projects WHERE id = '{$this->id}'")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['enddate'];
}
}
}
function file1() {
if ($result = mysql_query("SELECT `location` FROM project_screenshots WHERE pid = '{$this->id}'")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['location'];
}
}
}
function file2() {
if ($result = mysql_query("SELECT `location` FROM project_screenshots WHERE pid = '{$this->id}' AND id != '{$project->file1()}")) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);
return $row['location'];
}
}
}
}
?>[/code]

[Jessica]

too much code to look through without more info. What error do you get that makes you say it's "not working"

[chriscloyd]

Fatal error: Call to a member function file1() on a non-object in /home/srxstud/public_html/test22/includes/porfolio_getfunctions.php on line 55

[Jessica]

Okay this line:
if ($result = mysql_query("SELECT `location` FROM project_screenshots WHERE pid = '{$this->id}' AND id != '{$project->file1()}")) {

What is $project? Just like you use $this to reference id, a variable, you need to use it to call the methods.
$this->file1()

[chriscloyd]

didnt work

[Jessica]

[quote author=jesirose link=topic=124811.msg517694#msg517694 date=1170213728]
too much code to look through without more info. What error do you get that makes you say it's "not working"
[/quote]
I didn't mean just that one time dude. If all you can say is "didn't work", all the help you'll get is "tough luck"