Code that checks for filename of current page..? No idea where to start

[OhEmGee]

I'm an absolute newbie to php and was wondering if anyone could point me in the right direction, searching google/forums and everywhere else has been no help, I need to excute a peice of code on index.php only, how would I go about doing that..? Using a bit of common sense I'd guess that the code would need to check the current page, then something like an if statement so that if the filename is index.php, the code would work, but display something else if not. I hope that made sense!

[redarrow]

use $_GET[''];

 

example

 

<?php

index.php?cmd=page

if($_GET['cmd']=="page"){

//do some think

}else {

//do nothink

}

?>

[kenrbnsn]

That will not give the OP the name of the script that is being run. To get that you need to use the magic constant __FILE__.

 

Ken

[OhEmGee]

Sorry I'm not sure about that, how would I put that magic constant into the script..?

[trq]

Did you read the link to the manual page provided?

[kenrbnsn]

Did you look at the manual page I referenced in my answer?

 

Put this in a test script to see what it produces:

<?php
echo "This script is running from file: " . __FILE__;
?>

 

Ken

[OhEmGee]

Well I read the manual but none of it helps with what I'm trying to do, I tried this but it obviously doesn't work,

 

<?php

$index = "absolute/path/to/my/index.php"

if ( __FILE__ == $index ) {

  include("certain_file.php");

  }

?>

 

but I hope that makes it clearer for what I am trying to get. I'd like the code to check if the file is index.php and if so, then include the certain file.  ??? ??? Sorry I am still learning Php, it's difficult reading that manual because it's like I've been thrown into the deep end, I don't yet know how it all works.