Need help with php generated drop down list using date()

[offsprg01]

here's the code

 

				<select name="YEAR" size="1" style="width:100px">
				  <?php
				  	$current_year = date("Y");
					do {?>
						<option value="<?php echo $current_year; ?>" 
						<?php if ($yearText == $current_year) {?>
							selected="selected"> <?php echo $current_year; ?> </option>
						<?php } 
					while ($current_year != 2001);

				  ?>					  
				 </select>

 

am i doing this correctly? i think i am but apparently i'm not.

[Jessica]

It's just selected, not selected="selected".

 

What are you trying to do that isn't working? You never increment the year.

This could be accomplished with a slightly shorter for loop.

 

for($i=2001; $i<=date("Y"); $i++){
   print '<option value="'.$i.'"';
   if($yearText == $i){
      print ' selected';
   }
   print '>'.$i.'</option>';
}

[tom100]

I actually don't see any incrementing being done, unless I'm missing something.

 

The result would therefore be an infinite loop. You need to incriment it such as jesirose's example. Otherwise you PHP script will timeout.

[offsprg01]

lol i'm retarded i forgot to incriment currentdate. lol thanks guys. and thanks double for cleaning yup the loop for me jessie. big help

[pixeltrace]

hi,

 

my problem is also related to this.

 

how about in the case of the days?

let say the user selected

Jan

 

the day has to change in related to

the number of days that jan have

 

what is the code for this?

 

thanks!

[Jessica]

That would be javascript, and kind of worthless in time. You're going to have to check it serverside anyway with valid_date() (or whatever it is) so just go for 1-31 and give them an error after the fact if they mess with it.