Functions: optional arguments

[myron]

I have a function:

function splitPageResults($query, $max_rows, $count_key = '*', $page_holder = 'page')

I want to pass values for the first, second, and last arguments, but I want to use the default value for the third argument.  How do I do that?

[monk.e.boy]

I don't think you can  :(

 

monk.e.boy

[trq]

You can't.

[itsmeArry]

you are using the correct format for function

 

function splitPageResults($query, $max_rows, $count_key = '*', $page_holder = 'page')

 

it will do wht you need to do

 

call the function like

splitPageResults($query, $max_rows, '', $page_holder)

 

 

[MadTechie]

maybe store the value in a global var and use that!

[obsidian]

you are using the correct format for function

 

function splitPageResults($query, $max_rows, $count_key = '*', $page_holder = 'page')

 

it will do wht you need to do

 

Did you read the OP? What he's after is not possible, really, just as the other two replies have said.

 

@myron - Your best bet is to pass in a NULL and test for that within your actual function body. If it's empty, assign it your default value.

[myron]

Thanks to everyone who replied.  I'll try some of your suggestions.

[boo_lolly]

couldn't you write an 'if' statement inside the function to check if the parameter has been given, therefore handle the process differently?