is this possible?

[Fruddy]

Lets say that I have a content area and 2 buttons on a template:

 

button1:

<form action="#" method="POST">
<input  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />
</form>

 

and button2:

<form action="#" method="POST">
<input  type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>

 

if I press the first button I'll get some text in the content area... and if I press the second button I'll get some other text.

Is that possible?

 

[Orio]

Yeah. Give the buttons names and then check which button was pressed. Example:

 

<form action="#" method="POST">
<input name="button1"  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />
</form>

<form action="#" method="POST">
<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
<br><br>

<?php
if(isset($_POST['button1']))
echo "Button1 was pressed";
elseif(isset($_POST['button2']))
echo "Button2 was pressed";
else
echo "None of the buttons were pressed";
?>

 

 

Hope it helps

Orio.

[Fruddy]

Nope, it's not working  :-\

http://www.newcomedy.net/test.php

[Snooble]

post the form to itself.

 

<form action="test.php" method="POST">
<input name="button1"  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />
</form>

<form action="test.php" method="POST">
<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
<br><br>

<?php
if(isset($_POST['button1']))
echo "Button1 was pressed";
elseif(isset($_POST['button2']))
echo "Button2 was pressed";
else
echo "None of the buttons were pressed";
?>

[play_]

form action="#" method="POST">

<input name="button1"  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />

 

<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />

</form>

 

 

try that

[Fruddy]

Snooble, Play_ still not working. Tried both of your ideas.

http://www.newcomedy.net/test.php

[play_]

does your button MUST be of an image type?

 

if you can use regular submit buttons, this will work (tested):

<form action="#" method="POST">
<input name="button1"  type="submit" />

<input name="button2" type="submit" />
</form>

<?php
if(isset($_POST['button1'])) {
echo "Button1 was pressed";
} elseif(isset($_POST['button2'])) {
echo "Button2 was pressed";
} else {
echo "None of the buttons were pressed";
}
?>

 

 

[Orio]

My mistake, they are buttons so it should be this way:

 

<form action="#" method="POST">
<input name="button1"  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />
</form>

<form action="#" method="POST">
<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
<br><br>

<?php
if(isset($_POST['button1_x']))
echo "Button1 was pressed";
elseif(isset($_POST['button2_x']))
echo "Button2 was pressed";
else
echo "None of the buttons were pressed";
?>

 

 

Orio.

[AndyB]

If you use an image as a submit button, then the values returned are the x and y co-ordinates of your click relative to the top left corner of the image. Those values are returned as $_POST['submit_x'] and $_POST['submit_y'] for a button NAMEd submit.

 

Check for submit_x or submit_y being set and you'll have your form working in no time.

 

ok, Orio's noted it.

[Fruddy]

Well the images needs to be the buttons, and I dont think that submit type can do that.

 

But if this can be done in another way or without using forms, its ok. As long as its going to be the same outcome.

 

I'll try it Orio

[Snooble]

<form action="test.php" method="POST">
<input name="button1"  type="image" src="http://www.newcomedy.net/imgs/button_01.gif" />
</form>

<form action="test.php" method="POST">
<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
<br><br>

<?php
if(!isset($_POST['button1_x'] && ($_POST['button2_x']))
echo "None of the buttons were pressed";
elseif(isset($_POST['button2_x']))
echo "Button 2 was pressed";
elseif(isset($_POST['button1_x']))
echo "Button 1 was pressed";
?>

 

Snooble

 

(Balls. Orio is too damn fast, i had to look at my code)

[Fruddy]

Thanks very much guys! it works now!

 

But a new problem coming up..

 

 

This is the old code from my site:

www.newcomedy.net/home

 

It does not come out with the same output in test.php

www.newcomedy.net/test.php

[Snooble]

have you changed the form actions..

 

Snooble

 

[Fruddy]

Snooble, what do u mean?

 

 

this is my bottom code for the normal site:

<table border="0" cellspacing="0" cellpadding="0" align="center">
<tr>
<td width="212" height="51" background="http://www.newcomedy.net/imgs/home_06.gif">
</td>
<td width="168" height="51" background="http://www.newcomedy.net/imgs/button_01.gif">
<a href="http://www.newcomedy.net/home/business/" title="tryk her for at komme til business sektionen" onmouseover="businessOver()" onmouseout="businessOut()">
<img border="0" src="http://www.newcomedy.net/imgs/button_01.gif" alt="business info" name="business">
</a>
</td> 
<td width="116" height="51" background="http://www.newcomedy.net/imgs/home_08.gif"> 
</td>
<td width="168" height="51" background="http://www.newcomedy.net/imgs/button_02.gif">
<a href="http://www.newcomedy.net/home/creative/" title="tryk her for at komme til creative sektionen" onmouseover="creativeOver()" onmouseout="creativeOut()">
<img border="0" src="http://www.newcomedy.net/imgs/button_02.gif" alt="creative info" name="creative">
</a>
</td>
<td width="234" height="51" background="http://www.newcomedy.net/imgs/home_10.gif"> 
</td>
</tr>
</table>

 

 

Test.php bottom code:

<table border="0" cellspacing="0" cellpadding="0" align="center">
<tr>
<td width="212" height="51" background="http://www.newcomedy.net/imgs/home_06.gif">
</td>
<td width="168" height="51" background="http://www.newcomedy.net/imgs/button_01.gif">
<form action="test.php" method="POST">
<input name="button1" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
</td> 
<td width="116" height="51" background="http://www.newcomedy.net/imgs/home_08.gif"> 
</td>
<td width="168" height="51" background="http://www.newcomedy.net/imgs/button_02.gif">
<form action="test.php" method="POST">
<input name="button2" type="image" src="http://www.newcomedy.net/imgs/button_02.gif" />
</form>
</td>
<td width="234" height="51" background="http://www.newcomedy.net/imgs/home_10.gif"> 
</td>
</tr>
</table>

[Fruddy]

Nobody who knows what might be the problem?  :-\

[Fruddy]

Ok, I solved the problem with the design. But now the form script won't work  ???

 

www.newcomedy.net/home

 

php code:

 

<?
if(isset($_POST['button1_x']))
    echo "Button1 was pressed";
elseif(isset($_POST['button2_x']))
    echo "Button2 was pressed";
else
    echo "None of the buttons were pressed";
?>

[AndyB]

Please post your php code.  Looking at the generated html tells us nothing useful.

[Fruddy]

As I posted in my other topic, the PHP code for www.newcomedy.net/home looks like this:

 

<?

if(isset($_POST['button1_x']))

    echo "Button1 was pressed";

elseif(isset($_POST['button2_x']))

    echo "Button2 was pressed";

else

    echo "None of the buttons were pressed";

?>

 

The problem is that I allways get the "None of the buttons were pressed" text, though i pressed one of the buttons.

[Greaser9780]

<form action="#" method="POST">

<input name="button1"  type="submit"  value="image" src="http://www.newcomedy.net/imgs/button_01.gif" />

</form>

 

<form action="#" method="POST">

<input name="button2" type="submit"  value="image"  src="http://www.newcomedy.net/imgs/button_02.gif" />

</form>

<br><br>

 

<?php

if(isset($_POST['button1'])){

echo "Button1 was pressed";

}else{

        if(isset($_POST['button2']))

  echo "Button2 was pressed";

}else{

echo "None of the buttons were pressed";

}

?>

[Fruddy]

The type have to be image or else u cant use the src="http://www.newcomedy.net/imgs/button_01.gif".