davinci Posted March 9, 2006 Share Posted March 9, 2006 I added paging to one of my scripts and now the date doesn't show up. Can someone catch my mistake?At first I had this:[code]<?php include 'header.php' ?><?php include 'left.php' ?><?phpinclude 'library/config.php';include 'library/opendb.php';$id = $_GET['id'];if ($id == "") {$query = "SELECT id, name, path, title, thumbnail, playcount, DATE_FORMAT(entry_date, '%M %D %Y') FROM upload2 ORDER BY id DESC";$result = mysql_query($query) or die('Error, query failed');while(list($id, $name, $path, $title, $thumbnail, $playcount, $date) = mysql_fetch_array($result)) { ?><div align="center"><table cellpadding="2" width="100%" border="0" cellspacing="0" cellpadding="0"><tr><td width="30%"><a href="<?php echo $_SERVER['PHP_SELF'] ?>?id=<?= $id; ?>"><IMG BORDER="0" img src="media/thumbs/<?=$thumbnail;?>" height="80" width="80"><p></a></td><td width="70%"><a href="<?php echo $_SERVER['PHP_SELF'] ?>?id=<?= $id; ?>"><b><?php echo $title;?></b></a><br>Added on <?=$date;?><br>Plays: <?=$playcount;?> </td></tr></table>[/code]Now wherever I put <?=$date;?> I don't get anything...Then I changed it so that it has paging:[code]<?phpinclude 'library/config.php';include 'library/opendb.php';$id = $_GET['id'];if ($id == "") {$rowsPerPage = 6;$pageNum = 1; if(isset($_GET['page'])){ $pageNum = $_GET['page'];}$offset = ($pageNum - 1) * $rowsPerPage; $query = "SELECT id, name, path, title, thumbnail, playcount, DATE_FORMAT(entry_date, '%M %D %Y') FROM upload2 ORDER BY id DESC LIMIT $offset, $rowsPerPage";$result = mysql_query($query) or die('Error, query failed');?><div class="title">Video Archive</div><p><?phpwhile($row = mysql_fetch_array($result)) { ?><div align="center"><table cellpadding="2" width="75%" border="0" cellspacing="0" cellpadding="0"><tr><td width="50%"><a href="<?php echo $_SERVER['PHP_SELF'] ?>?id=<?= $row['id'];?>"><IMG BORDER="0" img src="media/thumbs/<?=$row['thumbnail'];?>" height="80" width="80"><p></a></td><td width="50%"><a href="<?php echo $_SERVER['PHP_SELF'] ?>?id=<?= $row['id'];?>"><b><?php echo $row['title'];?></b></a><br>Added on <?=$row['date'];?><br>Plays: <?=$row['playcount'];?> </td></tr></table><? } ?>[/code]Thank you to whoever can clear me up! Quote Link to comment https://forums.phpfreaks.com/topic/4501-date-not-showing-up/ Share on other sites More sharing options...
litebearer Posted March 9, 2006 Share Posted March 9, 2006 Could be just time for my meds, but....shouldn't this..[code]?id=<?= $row['id'];?[/code]be this...[code]?id=<?echo $row['id'];?[/code]Lite... Quote Link to comment https://forums.phpfreaks.com/topic/4501-date-not-showing-up/#findComment-15821 Share on other sites More sharing options...
obsidian Posted March 9, 2006 Share Posted March 9, 2006 [!--quoteo(post=353296:date=Mar 9 2006, 11:26 AM:name=litebearer)--][div class=\'quotetop\']QUOTE(litebearer @ Mar 9 2006, 11:26 AM) [snapback]353296[/snapback][/div][div class=\'quotemain\'][!--quotec--]Could be just time for my meds, but....shouldn't this..[code]?id=<?= $row['id'];?[/code]be this...[code]?id=<?echo $row['id'];?[/code]Lite...[/quote]actually, that's correct syntax. if you're only echoing a variable, you can use the shorthand <?= opening tag instead.as to the question at hand:you're formatting your date in your query, but you're not defining the results as "date", yet you're trying to echo "date" out of the array. i think you should be able to change your query to this and be ok:[!--sql--][div class=\'sqltop\']SQL[/div][div class=\'sqlmain\'][!--sql1--][span style=\'color:blue;font-weight:bold\']SELECT[/span] id, name, path, title, thumbnail, playcount, DATE_FORMAT(entry_date, [color=red]'%M %D %Y'[/color]) [color=green]AS[/color] date [color=green]FROM[/color] [color=orange]upload2[/color] [color=green]ORDER BY[/color] id [color=green]DESC[/color] LIMIT $offset, $rowsPerPage[!--sql2--][/div][!--sql3--]by using the "AS date", you are naming the results 'date' in your array, so you can just <?= $row['date'] ?> where you want it displayed.hope this helps Quote Link to comment https://forums.phpfreaks.com/topic/4501-date-not-showing-up/#findComment-15829 Share on other sites More sharing options...
davinci Posted March 9, 2006 Author Share Posted March 9, 2006 [!--quoteo(post=353305:date=Mar 9 2006, 12:00 PM:name=obsidian)--][div class=\'quotetop\']QUOTE(obsidian @ Mar 9 2006, 12:00 PM) [snapback]353305[/snapback][/div][div class=\'quotemain\'][!--quotec--]actually, that's correct syntax. if you're only echoing a variable, you can use the shorthand <?= opening tag instead.as to the question at hand:you're formatting your date in your query, but you're not defining the results as "date", yet you're trying to echo "date" out of the array. i think you should be able to change your query to this and be ok:[!--sql--][div class=\'sqltop\']SQL[/div][div class=\'sqlmain\'][!--sql1--][span style=\'color:blue;font-weight:bold\']SELECT[/span] id, name, path, title, thumbnail, playcount, DATE_FORMAT(entry_date, [color=red]'%M %D %Y'[/color]) [color=green]AS[/color] date [color=green]FROM[/color] [color=orange]upload2[/color] [color=green]ORDER BY[/color] id [color=green]DESC[/color] LIMIT $offset, $rowsPerPage [!--sql2--][/div][!--sql3--]by using the "AS date", you are naming the results 'date' in your array, so you can just <?= $row['date'] ?> where you want it displayed.hope this helps[/quote]You guys rock! Adding the "AS date" did the trick! Quote Link to comment https://forums.phpfreaks.com/topic/4501-date-not-showing-up/#findComment-15962 Share on other sites More sharing options...
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