[SOLVED] Separating a variable into 2

[denhamd2]

just wondering aswell, I have the month and year stored in a variable $thedate

 

so for example $thedate=042007

 

is there any way of splitting this up into 2 separate variables, $themonth and $theyear?

[jitesh]

$thedate=042007

 

$month = substr($thedate,0,2);

 

$year = substr($thedate,2,4);

 

[kenrbnsn]

You could also do it this way:

<?php
$thedate='042007';
list ($themonth,$theyear) = explode('-',date('m-Y',strtotime($thedate)));
echo $themonth . ' -- ' . $theyear;
?>

 

Ken

[denhamd2]

great thanks also finally one last small thing:

 

I have the day stored in a variable $day_num

 

its currently spitting out days 1-9 as "1", "2", etc.

 

is there any way of formatting $day_num to make it 2 digits, ie. "01", "02", etc?

[kenrbnsn]

Use the function sprint()

<?php
for ($day_num = 1;$day_num<10;$day_num++)
    echo sprintf("%02d",$day_num).'<br>';
?>

 

Ken

[jitesh]

if(strlen($day_num) == 1){

     $day_num = "0".$day_num ;

}

Ken has better idea

[denhamd2]

thanks

[denhamd2]

actually this seems to give a syntax error, any other ways of doing this?

[kenrbnsn]

What give a syntax error? You were given two solutions.

 

Ken

[denhamd2]

both i'm getting the unpected "{" error. I'm putting this in a while loop so thats probably why?

 

is there any simple php function that will format a number as 2 digits?

[trq]

Post your code!

[denhamd2]

heres the part in question:

 

//sets the first day of the month to 1
$day_num = 1;

//count up the days, untill we've done all of them in the month

while 
( $day_num <= $days_in_month ) 
{ 

echo "<td>$day_num<br><input name=\"$day_num$month$year\" type=\"checkbox\" value=\"yes\"></td>\n"; 
$day_num++; 
$day_count++;

[denhamd2]

any ideas guys?

[kenrbnsn]

Need to see more of your code. You show the start of the loop, but not the end.

 

Ken

[denhamd2]

here is the rest of the code:

 

//sets the first day of the month to 1
$day_num = 1;

//count up the days, untill we've done all of them in the month

while 
( $day_num <= $days_in_month ) 
{ 

echo "<td>$day_num<br><input name=\"$day_num$month$year\" type=\"checkbox\" value=\"yes\"></td>\n"; 
$day_num++; 
$day_count++;

//Make sure we start a new row every week
if ($day_count > 7)
{
echo "</tr><tr>";
$day_count = 1;
}

} 


//Finaly we finish out the table with some blanks if needed
while 
( $day_count >1 && $day_count <=7 ) 
{ 
echo "<td> </td>"; 

$day_count++;
}

[kenrbnsn]

The code you posted doesn't have any errors in it. We need to see more of your code and the exact error message.

 

Ken

[denhamd2]

actually figured it out myself, thanks for all your help :)

[kenrbnsn]

What was the problem & solution. This is for others who may read this thread.

 

Ken

[denhamd2]

think the problem was it wouldn't work because of the while loop but the solution was to use STR_PAD_LEFT

 

$myday_num = str_pad($day_num, 2, "0", STR_PAD_LEFT);