gettin this Warning ....

[dalmaca]

i am runnign a website witch is up and running fine...

decided to make a new site running the same script but slight changes ( layout / theme ect)

anyway i got another webserver ( the same as the real site is running, same host, same package ect )


but on the new site when i upload the sctrip and goto sign up i get this error

[code]Warning: gethostbyaddr(): Address is not a valid IPv4 or IPv6 address in / [/code]


any ideas ?

[hitman6003]

Apparently your not passing a valid IP address to your gethostbyaddr function.

There's no way we can help you beyond that point without seeing the code for at least that function.

[dalmaca]

this is where it says the error is ....

[code]
$host=gethostbyaddr("$REMOTE_ADDR"); <<<<<<<<<THIS LINE
$getbans =mysql_query("SELECT banned FROM $tab[banned];");
$bans = array();
while($ban=mysql_fetch_array($getbans)) {
  array_push($bans, $ban[0]);[/code]


the error on that line just thought id better post that whole section as it might of been needed

[AndyB]

Give this a shot ... and/or print the remote_addr to see if you're getting something that makes sense.
[code]$host=gethostbyaddr($_SERVER['REMOTE_ADDR']);[/code]

[dalmaca]

well the warning gone now ,

but it doesnt seem to let me goto step 2

ps its a sign up page , buti think thats sumthing my end ( on server its self)



Thnx

[phporcaffeine]

[!--quoteo(post=354302:date=Mar 12 2006, 04:11 PM:name=dalmaca)--][div class=\'quotetop\']QUOTE(dalmaca @ Mar 12 2006, 04:11 PM) [snapback]354302[/snapback][/div][div class=\'quotemain\'][!--quotec--]
well the warning gone now ,

but it doesnt seem to let me goto step 2

ps its a sign up page , buti think thats sumthing my end ( on server its self)
Thnx
[/quote]

$REMOTE_ADDR is a depriciated variable aside from the fact that there are several directives in PHP.INI that can stop vars like this. I imagine that you do not have access to PHP.INI on this server so you could try to pass the register_globals directive with ini_set if the host allows.

Your other option is to use the $_SERVER array as mentioned above. ( $_SERVER['REMOTE_ADDR'] )