Jump to content

Recommended Posts

heres the code

 

<?php
$host = "localhost";
$user = "";
$pass = "";
$dbname = "";

$con = mysql_connect($host,$user,$pass) or die (mysql_errno().": ".mysql_error()."<BR>");
mysql_select_db($dbname);

$query = "SELECT SUM(1) AS clicks, SUM(`clcpc`), SUM(`chcpc`) FROM `nuke_pnAffiliate_clicktracking` WHERE `pl` = 'rpu' AND  `date` > '20070228'AND `cl` IN (SELECT DISTINCT(cl) FROM rpu_sales WHERE salesman = 'ryan')";

$result = mysql_query($query);
$num_results = mysql_num_rows($result);
    
$row = mysql_fetch_assoc($result);

mysql_free_result($result);

echo $result;

?>

 

It brings up Resource id #5

 

where the myadmin brings up

 

clicks  SUM(`clcpc`)  SUM(`chcpc`)

87343 3423.2699509561 12342.159823611

Does this work OK and is it quicker?

 

SELECT COUNT(a.*) AS clicks, SUM(a.clcpc), SUM(a.chcpc) 
FROM `nuke_pnAffiliate_clicktracking` a
    INNER JOIN rpo_sales s ON a.cl = s.cl
WHERE a.`pl` = 'rpu' 
AND  a.`date` > '20070228'
AND s.salesman = 'ryan'

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.