include() question

[realjumper]

Hi,

 

I have a script to backup  a particular database. If I create another instance of this script I can backup a different database, and so on. If I have (say) 10 databases to backup, I would have to create 10 instances of this script. That's not the problem. The problem is that rather than create 10 cron jobs, I would like to have one file call the 10 scripts, with a 30 second interval between them. Then I would only need one cron job. Is there a way to have one script call other scripts? I have tried variations on the code below, but only the first script gets called.

 

<?php

include_once "backup_scripts/execute_db1_backup.php";

sleep(30);

include_once "backup_scripts/execute_db2_backup.php";

?>

[realjumper]

Never mind...I see why this won't work. I have another plan though :-)

[mpharo]

out of curiosity why wouldnt this work?

[realjumper]

Because if I include the two files, there are some function names in those two files that are the same, but do different tasks because they are for different databases. So I guess there is confusion in the script as to which function I am trying to call...because they both have the same name...._I think!_

[mmarif4u]

Yes u r right u have to if statement or switch statement.

 

Also i think u should change this:

include_once "backup_scripts/execute_db1_backup.php";

 

to this:

include_once ('backup_scripts/execute_db1_backup.php');

[neel_basu]

Also i think u should change this:

include_once "backup_scripts/execute_db1_backup.php";

 

to this:

include_once ('backup_scripts/execute_db1_backup.php');

Although I myself use () I think both of them will work.