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can use this code????


Andu Jame

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$ip1 = getenv('REMOTE_ADDR');
            $q="select * from kawalan_punch where id_kursus ='$id_kursus'";
            $are = mysql_query($q) or die("Error in $q\n" . mysql_error());
            $row=mysql_fetch_array($are);
            $ip2=$row["ip_client"];

 

I added a missing line.

 

Where does $id_kursus come from?

 

What do you want the code to do?

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If $id_kursus is different it will show error msg

 

Then you'll need some sort of check.

 

<?php

  $q = "select * from kawalan_punch where id_kursus ='$id_kursus'";
  if ($are = mysql_query($q)) {
    if (!mysql_num_rows($are)) {
      echo "id not found";
    } else {
      $row = mysql_fetch_array($are);
      $ip2 = $row["ip_client"];
    }
  } else {
    echo "Error in $q\n" . mysql_error();
  }

?>

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