Jump to content

calculating age


anatak

Recommended Posts

I want to calculate the age of some one.
so I want to substract 2 dates and then keep the year.
at this point I get the years of today's date and substract the year of the birthday date of the person.
but that means that every body's age changes at new year.

$now = date("Y-m-d");
$bday = $Row["UserBirthday"];
$age = $now-$bday;

is how I calculate the age of someone

I guess there is a way to substract two dates and round down to the year.

so does anybody kno how I can get the right number of years difference ?

anatak
Link to comment
Share on other sites

Your code may not return anything meaningful:
[code]<?php
$now = date("Y-m-d");
$bday = $Row["UserBirthday"];
$age = $now-$bday;
?>[/code]
The value of "$now" is a string, the subtraction might work because PHP will automatically turn a string like "2006-03-23" into 2006.

What you should do is something like:
[code]<?php
$hour = 3600; // number of seconds in an hour
$day = hour * 24; //number of seconds in a day (86400)
$yr = $day * 365.25; // number of seconds in a year, approximately
$now = strtotime('today'); // the number of seconds since 1-1-1970
$bday = strtotime($Row['UserBirthday']);  // I'm assuming that the format of $Row['UserBirthday'] is yyyy-mm-dd
$age = floor($now - $bday)/$yr;
echo $age;
?>[/code]

This algorithm will work all the time if the birthday is on or after 1-1-1970. On some systems it might work for earlier dates.

Ken
Link to comment
Share on other sites

here is my solution.
because of the problem wiht the range of dates I wrote the following function

here is the code that calls the function age()

[code]
If (substr($Row["UserBirthday"], 0, 4)=="0000"){
    $date=display_date_format($Row['UserBirthday']);
    $bday=substr($date, 0,strlen($date)-4).'secret';
    $age='secret';
}
else{
    
    $today = date("Y-m-d");
    $bday = $Row["UserBirthday"];
    $age= age($today, $bday);
    echo "function age: ".$age;
//    $age = $today-$bday;
    $bday = display_date_format($Row["UserBirthday"]);
}
[/code]

and here is the function age()
[code]
function age($arg01, $arg02)
{
    $today=$arg01;
    $bday=$arg02;
    echo $today ." today<br>";
    echo $bday . " birthday<br>";
    $todayyear=substr($today, 0, 4);
    $todaymonth=substr($today, 5, 2);
    $todayday=substr($today, 8, 2);

    $bdayyear=substr($bday, 0, 4);
    $bdaymonth=substr($bday, 5, 2);
    $bdayday=substr($bday, 8, 2);
    
    $age = $today - $bdayyear;
    if($todaymonth-$bdaymonth<=0){
        echo $age." month age -1<br>";
        $age--;
    }elseif($todayday-$bdayday<0){
        echo $age." day age -1<br>";
        $age--;
    }

    return $age;
}
[/code]
this works for me
thank you for looking into my problem
anatak
Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.