If...else question

[abisson]

Here you go! this is the code. I want to change the value of " aprouve ". In my sql data base it is either 1 or 0. What is wrong with this code?!

 

Thanks a lot!

 

-=PHP =-

 

while($donnee = mysql_fetch_array($query))

 

$donnee['aprouve']=$_POST['aprouve'];

if ($donnee['aprouve']=="1")

echo "oui";

elseif ($donnee['aprouve']=="0")

echo "non";

{

 

echo "<tr>";

echo "<td>" . $donnee['id_nouvelle'] .  "</td>";

    echo "<td>" . $donnee['titre'] . "</td>";

    echo "<td>" . $donnee['text'] . "</td>";

    echo "<td>" . $donnee['description'] . "</td>";

  echo "<td>" . $donnee['aprouve'] . "</td>";   

    echo "<td>" . $donnee['date_affichage'] . "</td>";

    echo "<td>";   

   

 

[trq]

What is wrong with this code?!

 

Why don't you tell us what the problem is? Eg; What do you expect to happen and what is actually happening?

[aim25]

First off you have a ton of syntax errors.

[LiamProductions]

Im new too PHP

 

but under the first block of code it has {  i thought it is suppose to be } 

 

 

[per1os]

$donnee['aprouve']=$_POST['aprouve'];      
if ($donnee['aprouve']=="1")
    echo "oui";
elseif ($donnee['aprouve']=="0")
   echo "non";   

while($donnee = mysql_fetch_array($query))  {      
      
       echo "<tr>";
      echo "<td>" . $donnee['id_nouvelle'] .  "</td>";
       echo "<td>" . $donnee['titre'] . "</td>";
       echo "<td>" . $donnee['text'] . "</td>";
       echo "<td>" . $donnee['description'] . "</td>";
         echo "<td>" . $donnee['aprouve'] . "</td>";       
       echo "<td>" . $donnee['date_affichage'] . "</td>";
       echo "<td>";   
}

 

I think thats what you were trying to get at.