Graphing with PHP using GD - error !

coool · July 12, 2007

hey guys,

I'm having problem when I'm excuting this code

<?php
        header ("Content-type: image/jpg");
        $img_handle = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($img_handle, 0, 10, 10);
        $txt_color = ImageColorAllocate ($img_handle, 233, 114, 191);
        ImageString ($img_handle, 31, 5, 5,  "My first Program with GD", $txt_color);
        ImagePng ($img_handle);
?>

This is the output:

‰PNG  IHDRæ£þÓêPLTE ér¿`ŽLÚIDAT(‘åÐ±AàŸMhF®!ža’+(„WÙË&ª;‘xë”Z…‡Ði'JD£RÑ+®0wÁ¯`«ÙýòÏfø³Sc CYeŸGEý˜õà«*T,(´ªšðñ£Peí|&H»;?&¦±éÖ³½54IÇ%¥öÉé¿×‘[¢•!‘i¡)1kg$;ÇP E‚˜o™¶²,{»—z÷·†…Âå:`Ž¾´¹Ì”¨Ž,³fSñƒ8Ÿ¨Æ7È½íEµ¯E´ª,ÒNçÛ@µ4&‚øg••Gé2ü¶'€£D?Ñ<_FIEND®B`‚

what's wrong with my code !

do you have any clue ?

Rojay · July 12, 2007

<?php
        header ("Content-type: image/jpg");
        $img_handle = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($img_handle, 0, 10, 10);
        $txt_color = ImageColorAllocate ($img_handle, 233, 114, 191);
        ImageString ($img_handle, 31, 5, 5,  "My first Program with GD", $txt_color);
        ImagePng ($img_handle);
?>

youre sending the headers as jpg but outputting png.. you either change the header to png or the output to jpg

coool · July 12, 2007

I fixed that.. but I've got same result

<?php
        header ("Content-type: image/png");
        $img_handle = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($img_handle, 0, 10, 10);
        $txt_color = ImageColorAllocate ($img_handle, 233, 114, 191);
        ImageString ($img_handle, 31, 5, 5,  "My first Program with GD", $txt_color);
        ImagePng ($img_handle);
?>

AndyB · July 12, 2007

There's nothing wrong with that code. It works perfectly uploaded to my GD-enabled server. Does your server support GD?

jchemie · July 13, 2007

Hey you need to graph?

If its for non commercial use, i would seriouly recommend using the jpgraph lib.

Check it out at

http://www.aditus.nu/jpgraph/

Thanks

Jyot

Yesideez · July 13, 2007

If you call phpinfo(); you can scroll down the output and check if GD is enabled.

coool · July 13, 2007

This is what's in my phpinfo about GD:

gd

GD Support enabled

GD Version bundled (2.0.28 compatible)

GIF Read Support enabled

GIF Create Support enabled

PNG Support enabled

WBMP Support enabled

XBM Support enabled

I think that means GD is enabled.. right ??

AndyB · July 13, 2007

Your code on my server works perfectly.

Are you 100% sure you uploaded your revised code to the same server folder as you're viewing to test the script?

lococobra · July 13, 2007

Works just fine for me.

coool · July 16, 2007

Your code on my server works perfectly.

Are you 100% sure you uploaded your revised code to the same server folder as you're viewing to test the script?

yes I'm sure..

what's ur GD criteria in phpinfo ?

keeB · July 16, 2007

Png doesnt work with IE natively. Are you using IE?

coool · July 16, 2007

Problem is solved..

I just saparated the codes..

image.php

<?php
        header ("Content-type: image/jpg");
        $image = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($image, 1, 10, 10);
        $text_color = ImageColorAllocate ($image, 233, 114, 191);
        ImageString ($image, 31, 5, 5,  "My first Program with GD", $text_color);
        ImagePng ($image);
?>

page.php

<html>

<body>

</body>

</html>

okay ! .. now how can have a graph ! with x-axis and y-axis taken from one table in MySQL query !

for example:

FruitsTable

fruitName numberAvailable

Apple 2

Orange 8

Banana 5

I want the x-axis to be my fruitName

and the y-axis to be the numberAvailable of the fruit

Query = "SELECT fruitName, numberAvailable FROM FruitsTable"

then ?

keeB · July 16, 2007

Oh, well your initial problem is page.php contained data before you were trying to output. In this case, what you did was semi-correct.

For performance reasons, you shouldn't have to render the image each time the page is loaded, maybe you should, it depends on what you're trying to achieve.

One last thing, if you don't want to use <img src="some.php"> you can output (using the same ImagePNG function) to a file, simply by changing the function call to look like:

<?php
        header ("Content-type: image/jpg");
        $image = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($image, 1, 10, 10);
        $text_color = ImageColorAllocate ($image, 233, 114, 191);
        ImageString ($image, 31, 5, 5,  "My first Program with GD", $text_color);
        ImageJPEG ($image, "nameofjpg.jpg");
?>

Barand · July 16, 2007

Easy way to graph is to have a simple bar graph

::bar.php::

<?php
// set dimensions
     $w = 102;
     $h = 20;
// create image
     $im = imagecreate($w, $h);
// set colours to be used
     $bg = imagecolorallocate($im, 0xE0, 0xE0, 0xE0);
     $black = imagecolorallocate($im, 0x00, 0x00, 0x00);
     $red  = imagecolorallocate($im, 0xFF, 0x00, 0x00);
       
// draw border
     imagerectangle($im, 0,0,$w-1,$h-1,$black);
// get value and max value from query string
     $val = isset($_GET['val']) ? $_GET['val'] : 0;
     $max = isset($_GET['max']) ? $_GET['max'] : 100; 
// calculate dimensions of inner bar
     $barw = $max ? floor(($w-2) * $val / $max) : 0;
     $barh = $h - 2;
// draw inner bar
      if ($barw)
     {
     	imagefilledrectangle($im, 1, 1, $barw, $barh, $red);
     }
// send image header
     header("content-type: image/png");
// send png image
     imagepng($im);
     imagedestroy($im);
?>

then

<?php
$ar = array(
    'Apple'  => 2,
    'Orange' => 8,
    'Banana' => 5
);

echo '<table>';
foreach ($ar as $fruit => $qty)
{
    echo "<tr><td>$fruit</td><td><img src='bar.php?val=$qty&max=10'></td></tr>";
}
echo '</table>';
?>

keeB · July 17, 2007

Great example, Barand!

coool · July 17, 2007

Oh, well your initial problem is page.php contained data before you were trying to output. In this case, what you did was semi-correct.

For performance reasons, you shouldn't have to render the image each time the page is loaded, maybe you should, it depends on what you're trying to achieve.

One last thing, if you don't want to use <img src="some.php"> you can output (using the same ImagePNG function) to a file, simply by changing the function call to look like:
<?php
        header ("Content-type: image/jpg");
        $image = ImageCreate (230, 20) or die ("Cannot Create image");
        $back_color = ImageColorAllocate ($image, 1, 10, 10);
        $text_color = ImageColorAllocate ($image, 233, 114, 191);
        ImageString ($image, 31, 5, 5,  "My first Program with GD", $text_color);
        ImageJPEG ($image, "nameofjpg.jpg");
?>

I've tried your code.. it doesn't work !

that's okay I'll stay with page.php and image.php

coool · July 17, 2007

Thanks Barand -- that's really a nice, simple, clear example

Barand · July 17, 2007

[

I've tried your code.. it doesn't work !

Mime type should be "image/jpeg"

header ("Content-type: image/jpeg");

coool · July 27, 2007

Thanks

I like the example !

but there're some things missing !

what i'm looking for is something like the attached picture

please take a look

[attachment deleted by admin]

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Graphing with PHP using GD - error !

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