PHP Arithmetic

[natalieG]

We  want to access  mysql table ad have  row  colors alternate, rows 1,3,5...=white and rows

2,4,6,8..=red.  if we have  a running row counter[$ROWCOUNT] Then we tried:

 

if ($ROWCOUNT %2 ==0){color=red;}else {color=white:}

$ROWCOUNT=$ROWCOUBNT + 1;

but all rows are white

 

Thanks,

 

Jennifer

[cmgmyr]

Here is what I usually do...

 

$rownum = 0;
while($row = $db->fetch($result)){
//DB stuff here

$tr = $rownum % 2;

echo "<tr class=\"tr".$tr."\">";

//out put information

echo "</tr>";

$x++;

}

 

in the css

.tr0{
background-color:red;
}

.tr1{
background-color:white;
}

 

...something like that, hope it helps

[sasa]

try

<?php
$ROWCOUBNT = 1;
for ($i = 1; $i < 10; $i ++){
if ($ROWCOUNT %2 ==0){echo 'red';}else {echo 'white';}
$ROWCOUNT=$ROWCOUNT + 1;
echo "<br />\n";
}
?>

it's work

look line $ROWCOUNT=$ROWCOUBNT + 1;

[roopurt18]

Slightly more concise:

<?php
$n = 0;
$colors = Array("red", "white");
for($i = 0; $i < 10; $i++){
  echo $colors[$n++ % 2] . "<br>";
}
?>