[SOLVED] How to get two keys from array loop?

[t_machine]

I have an array that stores ids, each of which is unique. Is there a way to run a for loop and get two keys at a time instead of only one?

 

Example

$id = array(1, 2, 3, 4, 5, 6);

 

for loop....

 

echo key 1

echo key 2

 

next loop

 

echo key 3

echo key 4

 

and so on....

 

Each key must not appear twice  so once a key is displayed, it will be removed from any further loops.

I need it to display two keys at a time because I will be pairing them up for the next part of the script.

 

Thanks for any help

 

 

[hitman6003]

for ($i = 0; $i < count($array); $i + 2) {
  echo $array[$i] . '<br />' . $array[$i + 1];
}

 

Probably want to put in a check to see if $array[$i + 1] exists...there is a potential for it not to.

[teng84]

maybe

$x=1;
for ($i = 0; $i < $x; $i) {
foreach($array as $y){
	// do something
$c++;
if($c==2) break;
}
if (count($array)!=$c) $x+=1;
}
not not tested and maybe thers better

[Fadion]

foreach($id as $value){
      echo $value . " - " .next($id) . "<br />";
}

[teng84]

i guess you have to explain or confirm the answer because your getting diff answer

[t_machine]

Thanks everyone

GuiltyGear is close to what  i need but the result repeats each keys

 

1 - 2

2 - 3

3 - 4

4 - 5

 

The perfect scenario would be the following

 

1 - 2

3 - 4

5 - 6

7 - 8

 

I tried the other two examples but my comp nearly crashed from the loops that kept continuing

[Fadion]

Thought u needed it that way. In this case the code provided by hitman6003 is your case. Probably they crashed cos in the first it is '$i + 2' and not '$i += 2' and in the second the $i is not incremented. Anyway this code should do it:

 

for($i=0; $i<count($id); $i += 2){
echo $id[$i] . ' - ' . $id[$i+1] . '<br />';
}

[hitman6003]

'$i + 2' and not '$i += 2' and in the second the $i is not incremented.

 

DOH!!

[Fadion]

lol. What i was saying is that u cant use $i+2 to increment $i by 2. U must use $i=$i+2 or simply $i += 2. At least at my side it is entering an endless loop. The other thing is that teng84 wrote a for loop without incrementing $i. But guess these arent important in an example code.

[t_machine]

Thanks very much. It works perfectly now