why would i be getting this error?

[ballhogjoni]

Notice: Use of undefined constant localhost - assumed 'localhost' in /home/realfina/public_html/freeCart/db.php on line 6

 

My connection code is:

<?php
$username="xxxxx";
$password="xxxxx";
$database="xxxxx";

$login = mysql_connect(localhost, $username, $password) or trigger_error(mysql_error(),E_USER_ERROR);
mysql_select_db($database);
?>

 

[cooldude832]

E_USER_ERROR is being treated as a constant and since your probably haven't named it thus the error

[teng84]

$login = mysql_connect(localhost, $username, $password)

should be

$login = mysql_connect('localhost', $username, $password) 

unless you define localhost

[cooldude832]

it could be both of them

[AndyB]

It's NOT an error, it's a (warning) notice.  Exactly what it says, and it assumes you mean the string 'localhost'

[dbo]

Where I come from warnings should be treated the same as errors But yes just put quotes around the thing!

[ballhogjoni]

I have some more Notices. They all just started all the sudden. I have been running these scripts a few weeks now and have never run into these issues.

 

Notice: Undefined index: title in /home/realfina/public_html/freeCart/add-edit.php on line 9

 

Notice: Undefined index: desc in /home/realfina/public_html/freeCart/add-edit.php on line 10

 

Notice: Undefined index: price in /home/realfina/public_html/freeCart/add-edit.php on line 11

 

this is the code that is making these notices.

 

<?php 
session_start(); 
include('db.php'); 
include('functions.php'); 
checkLogin('1 2');
$query = mysql_query("SELECT * FROM users WHERE ID = '{$_SESSION['user_id']}'");
$row = mysql_fetch_array($query) or die(mysql_error());
$Username = $row['Username'];
$title = $_POST['title'];
$desc = $_POST['desc'];
$price = $_POST['price'];
$title_checked = strip_tags($title);
$desc_checked = strip_tags($desc);
if (isset($title_checked) && isset($desc_checked) && isset($price)) {
if (!empty($title_checked) && !empty($desc_checked) && !empty($price)) {
if (strlen($title_checked) > 20 || strlen($desc_checked) > 30) {
		$leng = 'Please check the length of your Title and Description. Title is 20 Characters Max and Description is 30 Characters Max.';
} elseif (strlen($title_checked) <= 20 && strlen($desc_checked) <= 30) {
    		mysql_query("INSERT INTO products (Username, title, description, price) VALUES ('$Username','$title_checked','$desc_checked','$price')") or die(mysql_error());
		$verbage = '<span class="style5">Your product has been saved.</span>';
		unset($title,$desc,$price);
}
} else {
	$verbage = '<span class="style5">Product has NOT been Saved. Please enable Javascript & be sure to fill in all fields</span>';
	unset($title,$desc,$price);
}
}
?>

 

[Fadion]

Probably because Post variables arent still set. U may condition to assign those values if a Post variable exists.

[teng84]

undefine index maybe you are calling an index of an array that is not existing

 

check the forms for this

$title = $_POST['title'];

$desc = $_POST['desc'];

$price = $_POST['price'];

 

or show it here

[ballhogjoni]

<form action="" onsubmit="return validateFormOnSubmit(this)" method="POST">
		<div align="center">This form requires javascript to be enabled</div>
		<table align="right">
			<tr>
				<td align="right" class="style6">Title:</td>
				<td class="style6"><input type="text" name="title" /></td>
			</tr>
			<tr>
				<td align="right" class="style6">Description:</td>
				<td class="style6"><input type="text" name="desc" /></td>
			</tr>
			<tr>
				<td align="right" class="style6">Price:</td>
				<td class="style6"><input type="text" name="price" /></td>
			</tr>
			<tr>
				<td colspan="2" align="center"><input class="style6" type="submit" value="Add Product" /></td>
			</tr>
		</table>
		</form>

[teng84]

maybe your (js validateFormOnSubmit(this)) cheeck it

<form action="" onsubmit="return validateFormOnSubmit(this)" method="POST">

 

because you have empty form action so i believe it in the js