[SOLVED] Variable within a variable

[12dstring]

I have a list of 12 variables, like so

 

$d1=31;

$d2-28;

$d3=31;

$d4=30

....

$d12=31;

 

and another one called $month which is a numerical value from 1-12 (calculated seperately)

 

What I need is a variable, $dmonth, which is the value of $d"$month"

 

For example if $month=1 then $dmonth=$d1 (=31)

and likewise if $month=12, then $dmonth=$d12

 

I can't for the life of me figure out how to code a variable as part of a defined variable, so any help would be much appreciated.

 

Thanks in advance,

Dave

[Jessica]

$dmonth = $d.$month;

[akitchin]

not sure jesirose understood your question:

 

$varname = 'd'.$month;
echo 'days in this month: '.$$varname;

 

it might be smarter to use an array and simply define the indeces by month:

 

$d[1] = 31;
$d[2] = 28;
...

 

then to access the number of days, all you have to do is:

 

echo 'days in this month: '.$d[$month];

[Jessica]

When I read it the first time I read it the way you saw, then I read it again and thought it was different. Gah. *headdesk*

I had it right

[12dstring]

The array route sorted it a treat.

 

Thanks for the super-quick help guys