[SOLVED] Selecting 1 field from a Multi-Dimensional Array

[MasterACE14]

Evening Everyone,

 

I want to know how do I select just 1 field from a Multi-Dimensional Array.

I know how to select all the fields, by using the following format:

<?php
foreach($fields as $key => $val){
echo $val;
}

 

But how can I do a similar thing, but to just select 1 specific field, not all of them?

 

Regards ACE

[hemlata]

Hello,

 

If you know the 'key' for the multidimensional array then you can directly get the value as..

 

Eg. $array['key1'];

 

Hope this might solve your issue.

 

Regards,

[trq]

<?php

 $a = array(
   'foo' => array('a','b'),
   'bar' => array('x','y')
 );

 echo $a['foo'][1]; // echo 'b'

?>

[MasterACE14]

I understand your example. But I think it needs to be alittle different in my situation, and I dont know how. I am making a function that I will be able to use, to 1) select an Array, and 2) select 1 field from that Array.

 

Here is 1 of my arrays:

<?php
$weapons = array( array( id => 0,
					 weapon => "L85A2", 
					 price => 250,
					 damage => 15,
					 type => "Rifle",
					 rarity => "Basic",
					 description => "The L85A2 is a bullpup assault rifle, it is very powerful and a 
           				                 iron-sight comes standard.",
					 options => "You can give it a Laser."
					) );

 

and here is what I've got so far for the function:

<?php
// Select 1 field from an Array
function select_array($array,$field) {

return $array[$field]; 

}

 

in your example you had [1] after the ['foo'], in my case I dont think I need to use a numeric value. Am I able to use a string? something like this?

<?php
return $array[$field]['price']; 

or something like that?

[MasterACE14]

bump

[trq]

Am I able to use a string? something like this?

 

Of course. Why don't you try it and see?

[MasterACE14]

I setup my function like this:

<?php
// Select 1 field from an Array
function select_array($array,$field,$value) {

return $array[$field][$value]; 

}

 

and I tried this:

<?php echo select_array($weapons,"price",250); ?>

using the array I showed before.

 

And it doesnt echo anything  :-\

 

to me my function, logically doesnt seem to be correct. In your example you named your arrays, 'foo' and 'bar'. But in my Array their not named. It doesnt really seem possible for me to get past the $array part of my function, as my arrays arent named. :-\

[BlueSkyIS]

you passed the function the array $weapons, which contains 1 element which is an array. get hold of the internal array like this:

 

$array1 = $weapons[0];

 

then you can use the keys of $array1:

 

$id = $array1['id'];

$weapon = $array1['weapon'];

 

etc.

 

added: or to fix your code:

 

function select_array($array,$field) {

     return $array[0][$field][$value]; 

}

 

however, if you're going to store an array of arrays, you'll want to know which array in the array:

 

function select_array($elemnum, $array,$field) {

return $array[$elemnum][$field]; 

}

[teng84]

i think i get you! please show your sample array and sample output you want

 

[MasterACE14]

ok, my sample array is this:

<?php
$weapons = array( array( id => 0,
					 weapon => "L85A2", 
					 price => 250,
					 damage => 15,
					 type => "Rifle",
					 rarity => "Basic",
					 description => "The L85A2 is a bullpup assault rifle, it is very powerful and a 
           				                 iron-sight comes standard.",
					 options => "You can give it a Laser."
					) );

 

and say I wanted to echo the price. my output would be this:

250

 

now I just want my function to be able to do just that, select a specific field/value from the array. 

[MasterACE14]

Its working perfectly now!

<?php
// Select 1 field from an Array
function select_array($array,$num,$field) {

     return $array[$num][$field]; 

}

 

Thanks heaps guys 

 

Regards ACE